Question

如果work.length为4，我必须检查AResult in for循环如果4个AResult都是true，请设置result.setstatus("success"); 或result.setstatus("fail");
我该怎么办？

        for(int i = 0;i < work.length;i++){ 
            if(!work[i].contains("#")){                          
                CommandLineInterface CLI = new CommandLineInterface();
                String IP = null;
                boolean AResult;

                try {                       
                    AResult = CLI.Setting(work[i],"start"); //true or false                                     
                } catch (JSchException | InterruptedException e) {
                    e.printStackTrace();
                }       
            }        
        }
        //result.setstatus("success"); //all true
        //result.setstatus("fail");

Answer 1

添加一个计数器。当条件为true时递增它。循环后检查counter的值。像

这样的东西

int counter = 0;
for(int i = 0;i < work.length;i++){ 
    if(!work[i].contains("#")){                          
        CommandLineInterface CLI = new CommandLineInterface();
        String IP = null;
        boolean AResult;

        try {                       
            AResult = CLI.Setting(work[i],"start");
            if (AResult) {
                counter++;
            }                                     
        } catch (JSchException | InterruptedException e) {
            e.printStackTrace();
        }       
    }        
}
if (work.length == 4 && counter == 4) {
    result.setstatus("success");
} else {
    result.setstatus("fail");
}

您可以使用类似

的内容优化上述（并减小代码大小）

int counter = 0;
if (work.length == 4) { // <-- check the length first
    for (int i = 0; i < work.length; i++) {
        if (!work[i].contains("#")) {
            CommandLineInterface CLI = new CommandLineInterface();
            try {
                if (CLI.Setting(work[i], "start")) {
                    counter++; // <-- increment the counter.
                } else {
                    break; // <-- break on any fale.
                }
            } catch (Exception e) {
                e.printStackTrace();
            }
        }
    }
}
result.setstatus(counter == 4 ? "success" : "fail"); // <-- setstatus

Answer 2

试试这个，你真的不需要迭代循环直到结束时遇到错误的条件

 //initially set success
 result.setstatus("success");
 for(int i = 0;i < work.length;i++){ 
if(!work[i].contains("#")){                          
    CommandLineInterface CLI = new CommandLineInterface();
    String IP = null;


    try {                       
       if(CLI.Setting(work[i],"start"))
         {
         result.setstatus("fail");
           //no need to iterate further
           break;
        }                                 
    } catch (JSchException | InterruptedException e) {
        e.printStackTrace();
    }       
}

}

Answer 3

您还可以尝试以下代码

    boolean statusFlag = true; 
    for(int i = 0;i < work.length;i++){ 
        if(!work[i].contains("#")){                          
            CommandLineInterface CLI = new CommandLineInterface();
            String IP = null;
            boolean AResult;
            try {                       
                AResult = CLI.Setting(work[i],"start"); //true or false 
                if(!AResult){
                    statusFlag = false; 
                }
            } catch (JSchException | InterruptedException e) {
                e.printStackTrace();
            }       
        }        
    }
    if(statusFlag){
        result.setstatus("success"); 

    }else{
        result.setstatus("fail"); 
    }
}

java：在for循环中检查boolean

3 个答案: