Question

我有一个字符串，其中包含一些网址，如何从字符串中获取最后一个网址

$myString = "::http://www.example.com/test/2015/06/27/mob/image_285245.jpg::http://www.example.com/test/2015/06/27/mob/image_288733.jpg::http://www.example.com/test/2015/06/27/285245";

        $pattern = "/http:\/\/(.*?)\/\d/";
        preg_match($pattern, $myString, $results);
        echo $results[1];  

//I want this:
//http://www.example.com/test/2015/06/27/285245

Answer 1

使用以下代码，

<?php 
    $myString = "::http://www.example.com/test/2015/06/27/mob/image_285245.jpg::http://www.example.com/test/2015/06/27/mob/image_288733.jpg::http://www.example.com/test/2015/06/27/285245";
    $results = explode("::", $myString);
    echo end($results);
?>

<强>输出：

http://www.example.com/test/2015/06/27/285245

Answer 2

$myString = "::http://www.example.com/test/2015/06/27/mob/image_285245.jpg::http://www.example.com/test/2015/06/27/mob/image_288733.jpg::http://www.example.com/test/2015/06/27/285245";

$results = explode("::", $myString);

echo array_pop($results);

输出

http://www.example.com/test/2015/06/27/285245

从php中的preg_match获取最后一个值

2 个答案: