如何使这项工作?我正在尝试设置一个全局函数,以便我可以稍后调用它来进行原始输入,而不是在需要它的地方调用原始输入。
我认为我的本质达到了我所需要的程度,但我很难理解如何格式化,或者甚至可能。
提前谢谢。
def choice_1():
choice_1 == raw_input("> ")
def choice_1a():
choice_1a = raw_input("> ")
def choice_1b():
choice_1b = raw_input("> ")
编辑:我认为我的问题并不清楚。这是我正在处理的代码的更新,也许这会让事情变得清晰。
print "You've arrived at your desk"
def choice_1(one):
choice_1a = raw_input("< ")
def choice_1a():
choice_1a = raw_input("> ")
def choice_1b():
choice_1b = raw_input("> ")
#Choice_1
print "What do you want to do?"
print "We can \n1. Read\n2. Draw\n3. Work on homework"
print choice_1
#choice 1 branch 1
if choice_1 == "1":
print "What book should we read today?"
print "We can read\n1. Tom Sawyer\n2. Quantum Physics \n3. Ray Bradbury"
print choice_1a
if choice_1a == "1":
print "Great choice!"
if choice_1a == "2":
print "Heavy stuff there."
if choice_1a == "3":
print "Entertaining author, that one there!"
else:
print "Let's go to the library, maybe they'll have that one."
#choice 1 branch 2
if choice_1 == "2":
print "What would you like to draw?"
print "We can draw a\n1. Tiger\n2. Fish\n3. Bear "
print choice_1b
if choice_1b == "1":
print "You drew a Tiger!"
if choice_1b == "2":
print "You drew a Fish!"
if choice_1b == "3":
print "You drew a Bear!"
else:
print "Time for some improvisation."
#choice 1 branch 3
if choice_1 == "3":
print ""
这是否清楚一些混乱?
答案 0 :(得分:1)
这将做你想要的。正如@SethMMorton所指出的那样,你错过了return
def choice():
return raw_input('> ‘)
顺便说一句,这不是一件好事,因为对于阅读代码的人来说,choice
正在做什么并不会立即清楚。
我这样做了:
print 'Your name is :' + choice()
它按预期工作。
编辑:您应该制作if语句:
if choice() == "1"
:
答案 1 :(得分:0)
def multiplier(x, y):
ans = x * y
print ans
这将是一个功能的用途,当你准备好使用它时 像这样称呼它
multiplier(5, 10)
50