确定最常使用的变量/字段

时间:2015-06-26 22:26:09

标签: php

如果我有一个具有以下结构的数组,我需要确定最多使用哪个描述。

因此,在这种情况下,您可以看到在第一和第四组中使用了猫科动物,因此描述 - >猫科动物将是最常用的答案。如何在PHP中编写脚本以输出答案?

所以,如果我有一个名为$ stuff的数组:

 Array (

 [1] => Array (
        [Title] => Cat
        [Description] => Feline
        [Age] => 7

        ) 

 [2] => Array (
        [Title] => Dog
        [Description] => Canine
        [Age] => 8

        )

 [3] =>
       Array (
        [Title] => Birdie
        [Description] => Winged Beast of the Air
        [Age] => Eternal
       )

 [4] =>  
       (     
        [Title] => Kitten
        [Description] => Feline
        [Age] => 1
       )

 )

我找到了这段代码:

 $c = array_count_values($stuff); 
 $val = array_search(max($c), $c);

但这不起作用,因为我只需要计算Description字段,而不是所有字段。那么,我该如何进入并缩小范围或将其收紧,以便我只计算并获得匹配描述的数量。

我的想法是尝试:

 $c = array_count_values($stuff['Description']); 
 $val = array_search(max($c), $c);

但那没用。我错过了别的什么吗?

1 个答案:

答案 0 :(得分:1)

请检查以下内容: -

<?php
$stuff =  Array (
 '1' => Array (
        'Title' => 'Cat',
        'Description' => 'Feline',
        'Age' => 7

        ),
    '2' => Array (
        'Title' => 'Dog',
        'Description' => 'Caine',
        'Age' => 8

        ),
    '3' => Array (
        'Title' => 'Birdie',
        'Description' => 'Winged Beast of the Air',
        'Age' => 'Eternal'

        ),
 '4' => Array (     
        'Title' => 'Kitten',
        'Description' => 'Feline',
        'Age' => 1,
       )

 );


$description_count = array();
foreach ($stuff as $key=>$value) {
  // check and add to the description_count array
  if (isset($description_count[$value['Description']])) {
    $description_count[$value['Description']]++;
  }
  // if not exist then initialize 1
  else $description_count[$value['Description']] = 1;

 //in single line you can do it 
  $description_count[$value['Description']] = isset($description_count[$value['Description']]) ? $description_count[$value['Description']]++ : 1;
}
echo "<pre/>";print_r($description_count);

输出: - https://eval.in/388305