如何在Chef中自定义tomcat配方

Question

我一直在尝试自定义一个tomcat主厨配方，但我所做的一切似乎都没有改变tomcat的安装。我使用流浪汉即。

vagrant destroy && vagrant up

在Vagrantfile中

  config.vm.provision :chef_solo do |chef|
      chef.add_recipe "apt"
      chef.add_recipe "nginx-app"
      chef.add_recipe "tomcat-app"
   end

食谱/ Tomcat的应用程序/食谱/ default.rb

#
# Cookbook Name:: tomcat-app
# Recipe:: default

package "tomcat7" do
  action :install
end

食谱/ Tomcat的应用程序/ attributes.rb

node.default["tomcat"]["port"] = 8083 <-- can't seem to make this apply

谢谢，

Answer 1

我怀疑你正在写自己的tomcat食谱？节点属性覆盖仅适用于此处记录的开源烹饪书：

• java
• tomcat

实施例

这是一个利用流浪汉的测试厨房示例。

├── .kitchen.yml
├── Berksfile
└── test
    └── integration
        ├── default
        │   └── serverspec
        │       └── tomcat_spec.rb
        └── roles
            └── tomcat.json

＆＃34; tomcat＆＃34; role说明了如何设置运行列表并覆盖属性。

.kitchen.yml

---
driver:
  name: vagrant

provisioner:
  name: chef_zero

platforms:
  - name: ubuntu-14.04

suites:
  - name: default
    run_list:
      - role[tomcat]
    attributes:

测试/集成/角色/ tomcat.json

{
  "name": "tomcat",
  "description": "Runs tomcat with oracle JDK",
  "override_attributes": {
    "java": {
      "jdk_version": 8,
      "install_flavor": "oracle",
      "oracle": {
        "accept_oracle_download_terms": true
      }
    },
    "tomcat": {
      "base_version": 7,
      "port": 8081
    }
  },
  "run_list": [
    "recipe[apt]",
    "recipe[java]",
    "recipe[tomcat]"
  ]
}

Berksfile

Berkshelf自动从厨师超市下载食谱。

source 'https://supermarket.chef.io'

cookbook "apt"
cookbook "java"
cookbook "tomcat"

测试/集成/ serverspec / tomcat_spec.rb

require 'serverspec'

set :backend, :exec

describe service('tomcat7') do
  it { should be_running }
end

describe port('8081') do
  it { should be_listening }
end

describe process('java') do
  it { should be_running }
  its(:args) { should match /org.apache.catalina.startup.Bootstrap/ }
end