返回表中的member_number计数列表

Question

考虑下表

我需要按降序返回一个列表，其中 member_nr的数量在表where tournament = 'EPL' AND ROUND = '12'

中出现最频繁的

示例

该脚本应返回以下结果：

我想到了这个问题，我的逻辑问题就是这样的

第一步：GET member_nr逐一

 $sql = "SELECT DISTINCT * 
        FROM winners 
        WHERE tournament='$tour' AND round='$round'";
LOOP(){ //get 1 member number
$mem_nr = ['mem_nr']; //assign mem_nr to variable

第2步：获取计数（次数）^ ABOVE ^会员编号出现在表格中

  "$sql="SELECT *, count(member_nr) as nrWins 
   FROM winners 
   where member_nr ='$memNr' and tournament='$tournament' AND     round='$round'";"
 LOOP(){//get count

第3步：显示数据

echo $row=['nrWins'] //Display Number Wins
echo $memNr
   }//END LOOP
 }//END LOOP

我的问题：

以上对我来说似乎不是很有效，我正在寻找最简单有效的方法来返回上表中的会员数量，欢迎任何想法/建议

Answer 1

尝试这样的事情：

SELECT *, COUNT(*) AS `wins`
FROM `winners`
WHERE `tournament` = '$tournament'
  AND `round` = '$round'
GROUP BY `member_nr`
ORDER BY `wins` DESC

Answer 2

IEnumerable