我似乎无法弄清楚为什么会这样做:
我有这样的功能设置:
func (srv *Server) StartServer() {
// Some stuff to make sure paths are correct
path := srv.Path + "server.exe"
var args = []string{
"ip=" + srv.IP,
"un=" + srv.Username,
"pw=" + srv.Password
}
proc, err := os.StartProcess(path, args, new(os.ProcAttr))
if err != nil {
panic(err)
}
}
StartProcess方法抛出的索引超出范围。
我可能只是遗漏了一些东西,但我看不到它。
请求的确切错误:
panic: runtime error: index out of range
goroutine 1 [running]:
syscall.StartProcess(0xc082052b70, 0x21, 0xc08200a6e0, 0x5, 0x5, 0xc08201dd60, 0x0, 0x0, 0x0, 0x0)
c:/go/src/syscall/exec_windows.go:322 +0x94c
os.startProcess(0xc082052b70, 0x21, 0xc08200a6e0, 0x5, 0x5, 0xc08200a730, 0x5217e0, 0x0, 0x0)
c:/go/src/os/exec_posix.go:45 +0x482
os.StartProcess(0xc082052b70, 0x21, 0xc08200a6e0, 0x5, 0x5, 0xc08200a730, 0x0, 0x0, 0x0)
c:/go/src/os/doc.go:24 +0x79
main.(*Server).StartServer(0x5efae0)
E:/build_test/SrvMgr.go:85 +0x4e6
main.main()
E:/build_test/SrvMgr.go:54 +0x141
goroutine 2 [runnable]:
runtime.forcegchelper()
c:/go/src/runtime/proc.go:90
runtime.goexit()
c:/go/src/runtime/asm_amd64.s:2232 +0x1
goroutine 3 [runnable]:
runtime.bgsweep()
c:/go/src/runtime/mgc0.go:82
runtime.goexit()
c:/go/src/runtime/asm_amd64.s:2232 +0x1
goroutine 4 [runnable]:
runtime.runfinq()
c:/go/src/runtime/malloc.go:712
runtime.goexit()
c:/go/src/runtime/asm_amd64.s:2232 +0x1
exit status 2
编辑:链接到简化的play.golang后复制它。我正在运行版本1.4.2 win / amd64
答案 0 :(得分:2)
您收到错误是因为您没有在os.ProcAttr上为Stderr和Stdout设置文件描述符。似乎那些在linux上自动设置,但你需要在windows上设置它们。
这是一个有效的例子:
func (srv *Server) StartServer() {
// Some stuff to make sure paths are correct
path := srv.Path + "server.exe"
var args = []string{
"ip=" + srv.IP,
"un=" + srv.Username,
"pw=" + srv.Password
}
var attr os.ProcAttr
attr.Files = []*os.File{nil, os.Stdout, os.Stderr}
proc, err := os.StartProcess(path, args, &attr)
if err != nil {
panic(err)
}
}