Question

我试图通过foreach循环显示来自JSON响应的数据。但是，如果我尝试，我会收到此错误：

为foreach（）提供的参数无效

我放在foreach循环中的数据不为空或空，我检查过。

我的代码：

$json = file_get_contents($goodurl);
$the_data = json_decode($json, true);
$count = 0;
foreach($the_data->response as $video)
{
//case show results as text only
//echo $video->title;
$html.= "<p><div class='p2go_title'><a href='". $video->playbackUrl ."' target='_blank'>" . $video->title . "</a></div>";
$html.= "<div class='p2go_contributors'>By: ". $video->contributors ."</div>";
$html.= "<div class='p2go_views'>Views: ". $video->views ."</div></p>";

$count++;
}
return $html;

Answer 1

由于您要将json_decode设置为返回数组，因此请将其作为array访问，而不是object。

$the_data = json_decode($json, true); // if you set 2nd paramater to true, it will return an array

foreach($the_data['response'] as $video)
{
   $html.= "<p><div class='p2go_title'><a href='". $video['playbackUrl']."' target='_blank'>" . $video['title'] . "</a></div>";
   $html.= "<div class='p2go_contributors'>By: ". $video['contributors'] ."</div>";
   $html.= "<div class='p2go_views'>Views: ". $video['views'] ."</div></p>";

 $count++;
}

Answer 2

$the_data是数组。试试 -

foreach($the_data['response'] as $video)

json_decode($json, true);将返回一个数组。第二个参数仅用于此。

<强>更新

内部元素也需要作为数组加入 -

$html.= "<p><div class='p2go_title'><a href='". $video['playbackUrl'] ."' target='_blank'>" . $video['title'] . "</a></div>";
$html.= "<div class='p2go_contributors'>By: ". $video['contributors'] ."</div>";
$html.= "<div class='p2go_views'>Views: ". $video['views'] ."</div></p>";

foreach循环与解码的json数据

2 个答案: