循环列表以获取密钥＆amp;使用Java的值对

Question

这是我收到的回复：

[{rollno=1066276530, rollvalue=1815401000238}] 

这是强制转换为List<Map<String, String>> leadIds。现在我想迭代这些leadIds以获得关键＆amp;价值对。我已经尝试过这种方式，但是返回键为“1066276530”，值为“rollno”，而我期望键为“1066276530”，值为“1815401000238”。

这是我的代码

for (Map<String, String> map : leadIds) {
    for (Map.Entry<String, String> entry : map.entrySet()) {
        String rollno = String.valueOf(entry.getValue());
        String rollvalue = String.valueOf(entry.getKey());
        LOG.info("[Status Search] Roll No:" +rollno
            + " Roll value:" + rollvalue);
    }
}

Answer 1

查看您的日志声明。您已切换了号码和ID：

LOG.info("[Status Search] Application ID :"+applicationNumber+
    " Application Number :"+appId);

应该是：

LOG.info("[Status Search] Application ID :"+appId+
    " Application Number :"+applicationNumber);

Answer 2

试试这个

 for (Map<String, String> map : leadIds) {
    for (Map.Entry<String, String> entry : map.entrySet()) {
        String applicationNumber = String.valueOf(entry.getkey());
        String appVal = String.valueOf(entry.getValue());
        LOG.info("[Status Search] Application ID :"+applicationNumber+" Application Number :"+appVal);
}

}

Answer 3

Actually you don't need two loops to achieve this, your outer loop map contains the values for the keys rollno and rollvalue, so get it from there.

for (Map<String, String> map : leadIds) {
    String applicationNumber = map.get("rollno");
    String appId = map.get("rollvalue");
    LOG.info("[Status Search] Application ID:"+ applicationNumber + " Application Number:" + appId);
}