如何在android中使用if else语句为radiobuttons

Question

我在一个RadioGroups中有两个layout，每个radiogroup有三个radio buttons。那么如何使用if else statement。

[每个组中有两个radiogroups有三个radiobuttons。当用户点击一个单选按钮时，它会显示正确的答案。错误答案。] [1]

Answer 1

为什么要使用if else语句？你可以轻松地完成它。

 int radioButtonId = rbGroup.getCheckedRadioButtonId();
 View radioButton = radioButtonGroup.findViewById(radioButtonId);

Answer 2

您可以这样做以从radioGroup

获取已检查的radiobutton

RadioGroup g = (RadioGroup) findViewById(R.id.rBtnDigits);

switch (g.getCheckedRadioButtonId())
{
case R.id.rbtnButton1
//do something
break;

case R.id.rbtnButton2
//do something
break;
}

Answer 3

rg = (RadioGroup) findViewById(R.id.radioGroup1);
    button = (RadioButton) findViewById(R.id.radio0);

    rg.performClick();
    rg.setOnCheckedChangeListener(new OnCheckedChangeListener() { 

 public void onCheckedChanged(RadioGroup group, int checkedId) {
            // TODO Auto-generated method stub

            @SuppressWarnings("unused")
            int selected = rg.getCheckedRadioButtonId();

            pos = rg.indexOfChild(findViewById(rg.getCheckedRadioButtonId()));

            switch (pos) {
            case 0:
                Toast.makeText(getBaseContext(),
                        "You have Clicked RadioButton 1",
                        Toast.LENGTH_SHORT).show();
                break;
            case 1:
                Toast.makeText(getBaseContext(),
                        "You have Clicked RadioButton 2",
                        Toast.LENGTH_SHORT).show();
                break;
            case 2:
                Toast.makeText(getBaseContext(),
                        "You have Clicked RadioButton 3",
                        Toast.LENGTH_SHORT).show();
                break;
            default:
                Toast.makeText(getBaseContext(),
                        "You have Clicked RadioButton 4",
                        Toast.LENGTH_SHORT).show();
                break;

            }
        }

    });