我有commad-line工具,它发送广播和等待结果。
服务器代码(省略错误处理):
int makeAddr(const char* name, struct sockaddr_un* pAddr, socklen_t* pSockLen)
{
int nameLen = strlen(name);
pAddr->sun_path[0] = '\0';
strcpy(pAddr->sun_path+1, name);
pAddr->sun_family = AF_LOCAL;
*pSockLen = 1 + nameLen + offsetof(struct sockaddr_un, sun_path);
return 0;
}
int main(int argc, char* argv[])
{
//...
// Create socket in abstract namespace
struct sockaddr_un sockAddr = {0};
socklen_t sockLen;
makeAddr("SOCKET_NAME", &sockAddr, &sockLen);
int serverFd = socket(AF_LOCAL, SOCK_STREAM, PF_UNIX));
bind(serverFd, (const struct sockaddr*) &sockAddr, sockLen);
listen(serverFd, 5);
//set socket non-blocking
int flags = fcntl(serverFd, F_GETFL, 0);
fcntl(serverFd, F_SETFL, flags | O_NONBLOCK);
pollfd pollFd = {0};
pollFd.fd = serverFd;
pollFd.events = POLLIN | POLLRDHUP;
// Send brodcast
system("am broadcast ...");
for(;;)
{
// Wait result
int pollResult = poll(&pollFd, 1, timeout);
// Process result
Java客户端代码:
public class CommandReceiver extends BroadcastReceiver{
@Override
public void onReceive(Context context, Intent intent) {
LocalSocket socket = new LocalSocket();
LocalSocketAddress address = new LocalSocketAddress("SOCKET_NAME", LocalSocketAddress.Namespace.ABSTRACT);
socket.connect(address);
// Do something and send result asynchronously
这一切都适用于Android之前的5.1。
在android 5.1上,connect()抛出异常:
java.io.IOException:Permission denied
在android.net.LocalSocketImpl.connectLocal(原生方法)
在android.net.LocalSocketImpl.connect(LocalSocketImpl.java:290)
在android.net.LocalSocket.connect(LocalSocket.java:130)
在日志中有错误:
07-27 09:56:08.179:W:type = 1400 audit(0.0:3675):avc:拒绝{connectto} for path = 00636F6D2E6B6173706572736B792E6B617368656C6C2E534F434B45542D36313838363731373231343337393833373637 scontext = u:r:untrusted_app:s0 tcontext = u:r:shell :s0 tclass = unix_stream_socket permissive = 0
我发现了相对的android修复: https://android.googlesource.com/device/moto/shamu/+/b2db40f
那么,自从Android 5.1以后它将不再起作用了? 我能做些什么(可能以某种方式设置权限)? 或者是否有另一种机制从本机命令行工具发送数据并等待结果?
答案 0 :(得分:1)
使用管道代替套接字: O_RDWR on named pipes with poll()
在java进程中创建管道:
mkfifo(cpath, 0);
chmod(cpath, S_IRWXU|S_IROTH|S_IRGRP);
在本机进程中打开管道:
int serverFd = open(PIPE_NAME, O_RDONLY | O_NONBLOCK);
pollfd pollFd = {0};
pollFd.fd = serverFd.get();
pollFd.events = POLLIN | POLLRDHUP;
// send command
....
for(;;)
{
int pollResult = poll(&pollFd, 1, timeout);