Question

我正在创建一个插件，通过编码的URL从外部服务器获取数据。为了解码插件的输出我正在使用JsonDecode，但它每次都会返回'NULL'。

代码：

    $json = file_get_contents($goodurl);
    $data = json_decode($json);
    var_dump($data);

这是请求网址时的响应：

{
  "schemaVersion": "1.0",
  "catalogueVersion": "4.0.5651.20898",
  "encoding": "UTF-8",
  "action": "info",
  "query": "catalogue",
  "success": "true",
  "response": {
    "title": "Presentations 2Go",
    "description": "Presentations2Go videoserver is an innovative solution to simply capture presentations and\/or lectures on video. The video image of the presenter is linked with the presentation and stored for later (re)use.",
    "logoUrl": "https:\/\/DEMO-FORMS.presentations2go.eu\/P2G\/images\/logo\/logo.png",
    "languages": [
      {"lang": "en"},
      {"lang": "nl"},
      {"lang": "de"},
      {"lang": "fr"},
      {"lang": "kr"},
      {"lang": "no"},
      {"lang": "pt"},
      {"lang": "dk"},
      {"lang": "cn"},
      {"lang": "ar"},
      {"lang": "se"},
      {"lang": "it"},
      {"lang": "es"},
      {"lang": "ru"},
      {"lang": "cy"},
      {"lang": "tw"}
    ],
    "videoCount": "380",
    "webmaster": "support@presentations2go.eu"
  }
}

这是JSON中的输出：

object(stdClass)#83 (7) { 

    ["schemaVersion"]=> string(3) "1.0" 

    ["catalogueVersion"]=> string(14) "4.0.5651.20898" 

    ["encoding"]=> string(5) "UTF-8" 

    ["action"]=> string(4) "info" 

    ["query"]=> string(9) "catalogue" 

    ["success"]=> string(4) "true" 

    ["response"]=> object(stdClass)#84 (6) { 

        ["title"]=> string(17) "Presentations 2Go" 

        ["description"]=> string(207) "Presentations2Go videoserver is an innovative solution to simply capture presentations and/or lectures on video. The video image of the presenter is linked with the presentation and stored for later (re)use." 

        ["logoUrl"]=> string(63) "https://DEMO-FORMS.presentations2go.eu/P2G/images/logo/logo.png" 

        ["languages"]=> array(16) { 

            [0]=> object(stdClass)#85 (1) { 

                    ["lang"]=> string(2) "en" 

                } 
                [1]=> object(stdClass)#86 (1) { 

                    ["lang"]=> string(2) "nl" 

                } 
                [2]=> object(stdClass)#87 (1) { 

                    ["lang"]=> string(2) "de" 

                } 
                [3]=> object(stdClass)#88 (1) {

                    ["lang"]=> string(2) "fr"

                } 
                [4]=> object(stdClass)#89 (1) {

                    ["lang"]=> string(2) "kr"

                } 
                [5]=> object(stdClass)#90 (1) {

                    ["lang"]=> string(2) "no"

                } 
                [6]=> object(stdClass)#91 (1) {

                    ["lang"]=> string(2) "pt"

                } 
                [7]=> object(stdClass)#92 (1) { 

                    ["lang"]=> string(2) "dk"

                } 
                [8]=> object(stdClass)#93 (1) {

                    ["lang"]=> string(2) "cn"

                } 
                [9]=> object(stdClass)#94 (1) { 

                    ["lang"]=> string(2) "ar"

                } 
                [10]=> object(stdClass)#95 (1) {

                    ["lang"]=> string(2) "se" 

                } 
                [11]=> object(stdClass)#96 (1) { 

                    ["lang"]=> string(2) "it" 

                } 
                [12]=> object(stdClass)#97 (1) { 

                    ["lang"]=> string(2) "es" 

                } 
                [13]=> object(stdClass)#98 (1) { 

                    ["lang"]=> string(2) "ru" 

                } 
                [14]=> object(stdClass)#99 (1) { 

                    ["lang"]=> string(2) "cy" 

                } 
                [15]=> object(stdClass)#100 (1) {

                    ["lang"]=> string(2) "tw" 

                } 
            } 

        ["videoCount"]=> string(3) "378" 

        ["webmaster"]=> string(27) "support@presentations2go.eu" 
    } 

}

我不是那种经验丰富的JSON所以我怀疑那里可能存在语法错误。但我不确定是什么以及如何解决它。

Answer 1

您正在获取对象而不是数组。只需写下：

$data = json_decode($json, true);

接收关联数组。

来自文档：http://php.net/manual/en/function.json-decode.php

Answer 2

使用此代码

 $data = json_decode($json,true);

Answer 3

您正在获取一个对象而不是一个数组。

接收关联数组。

$data = json_decode($json, true);

或者您可以访问或获取对象的值，如

echo $data->catalogueVersion;

Answer 4

每个人都已经告诉过你将json_decode设置为true，当真正返回的对象将被转换为关联数组时，link

$data = json_decode($json, true);

我建议使用以下代码查看您的数组。它更容易阅读。

echo "<pre>";
print_r($array);
echo "</pre>";

Json在URL上的Null上编码

4 个答案: