我想创建以下XML。
<?xml version="1.0" encoding="utf-8"?>
<MyNode xsi:schemaLocation="https://MyScheme.com/v1-0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="https://MyScheme.com/v1-0 Sscheme.xsd">
<MyInfo>
<MyNumber>string1</MyNumber>
<MyName>string2</MyName>
<MyAddress>string3</MyAddress>
</MyInfo>
<MyInfo2>
<FirstName>string4</FirstName>
</MyInfo2>
</MyNode>
我正在使用此代码。
XNamespace xmlns = "https://MyScheme.com/v1-0 Sscheme.xsd";
XNamespace xsi = XNamespace.Get("http://www.w3.org/2001/XMLSchema-instance");
XNamespace schemaLocation = XNamespace.Get("https://MyScheme.com/v1-0");
XDocument xmlDocument = new XDocument(
new XElement(xmlns + "MyNode",
new XAttribute(xsi + "schemaLocation", schemaLocation),
new XAttribute(XNamespace.Xmlns + "xsi", xsi),
new XElement("MyInfo",
new XElement("MyNumber", "string1"),
new XElement("MyName", "string2"),
new XElement("MyAddress", "string3")
),
new XElement("MyInfo2",
new XElement("FirstName", "string4")
)
)
);
xmlDocument.Save("C:\\MyXml.xml");
然而，我得到了xmlns =＆＃34;＆＃34;内部标签MyInfo和MyInfo2。
有人可以帮我创建正确的XML吗？
答案 0 :(得分：1)
您需要对所有元素使用XNamespace XDocument xmlDocument = new XDocument(
new XElement(xmlns + "MyNode",
new XAttribute(xsi + "schemaLocation", schemaLocation),
new XAttribute(XNamespace.Xmlns + "xsi", xsi),
new XElement(xmlns+"MyInfo",
new XElement(xmlns+"MyNumber", "string1"),
new XElement(xmlns+"MyName", "string2"),
new XElement(xmlns+"MyAddress", "string3")
),
new XElement(xmlns+"MyInfo2",
new XElement(xmlns+"FirstName", "string4")
)
)
);
，因为这是默认命名空间，并且它在根级别元素处声明。请注意，除非另有说明，否则后代元素会隐式继承祖先默认命名空间：
class Character {
constructor(){
if(Object.getPrototypeOf(this) === Character.prototype){
console.log('invoke character');
}
}
}
class Hero extends Character{
constructor(){
super(); // throws exception when not called
console.log('invoke hero');
}
}
var hero = new Hero();
console.log('now let\'s invoke Character');
var char = new Character();