Want to count each individual employee's presents and absents

Question

i've created a employee attendance table having 3 columns emp_name, emp_present & date,

there is no primary key in mytable

i'm using this query to get total presents of employees

  SELECT `emp_name`, `emp_present`,(select sum(emp_present='present') 
  from empattendance) as 'total presents', `date` FROM `empattendance` where date=curdate()

but i want to get total presents and 'total absents' of each indiviual shown with them in total presents and 'total absents' column respectively. I'm a newbie in database and don't have much knowledge about how to sort this problem.....

Answer 1

You can use conditional aggregation, to get the count of rows where employee was present and the count of rows where employee was absent like this:

SELECT emp_name, 
  SUM(emp_present = 'present') AS numPresence, 
  SUM(emp_present = 'absent') AS numAbsence
FROM employees
GROUP BY emp_name;

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EDIT:

If you want a running total of presence and absences, you'll need to use a variable:

SET @present := 0;
SET @absent := 0;
SELECT emp_name, dateColumn, 
   IF(emp_present = 'present', @present := @present + 1, @present) AS numPresence
   IF(emp_present = 'absent', @absent := @absent+ 1, @absent) AS numAbsense
FROM myTable
ORDER BY dateColumn;