Question

如何配置rails控制器，这样我就可以让用户在任何比赛中发布提交内容。当他们发布用户ID时，竞赛ID应自动附加到提交内容。

我知道我能做到：

User.first.contests.create =＆gt;让用户创建比赛
Contest.first.submissions.create =＆gt;在比赛中创建提交（未链接到用户）
User.first.submissions.create =＆gt;创建链接到用户而不是竞赛的提交
我不能做User.first.Contest.last.submissions.create =＆gt;我想将提交内容链接到竞赛和到提交。

有没有一种优雅的方法来解决这个问题？

提交控制器如下所示：

class SubmissionsController < ApplicationController
  before_action :set_submission, only: [:show, :edit, :update, :destroy]

  # the current user can only edit, update or destroy if the id of the pin matches the id the user is linked with.
  before_action :correct_user, only: [:edit, :update, :destroy]
  # the user has to authenticate for every action except index and show.
  before_action :authenticate_user!, except: [:index, :show]


  respond_to :html

  def index
    @title = t('submissions.index.title')

    @submissions = Submission.all
    respond_with(@submissions)
  end

  def show
    @title = t('submissions.show.title')

    respond_with(@submission)
  end

  def new
    @title = t('submissions.new.title')

    @submission = Submission.new
    respond_with(@submission)
  end

  def edit
    @title = t('submissions.edit.title')

  end

  def create
    @title = t('submissions.create.title')

    @submission = Submission.new(submission_params)
    @submission.save
    respond_with(@submission)
  end

  def update
    @title = t('submissions.update.title')

    @submission.update(submission_params)
    respond_with(@submission)
  end

  def destroy
    @title = t('submissions.destroy.title')

    @submission.destroy
    respond_with(@submission)
  end

  private
    def set_submission
      @submission = Submission.find(params[:id])
    end

    def submission_params
      arams.require(:submission).permit(:reps, :weight, :user_id)
    end

    def correct_user
      @submission = current_user.submissions.find_by(id: params[:id])
      redirect_to submissions_path, notice: t('submissions.controller.correct_user') if @submission.nil?
    end

end

我有以下模特：

class Contest < ActiveRecord::Base
  has_many :submissions
  has_many :users, through: :submissions

class Submission < ActiveRecord::Base
  belongs_to :user
  belongs_to :contest

class User < ActiveRecord::Base
  has_many :submissions
  has_many :contests, through: :submissions

Answer 1

您是否可以在@submission = current_user.submissions.new(submission_params)

中使用@contest = Contest.find(params[:contest_id])和SubmissionsController#create

编辑：我已添加了一些有关在contest_id表格中添加对submissions的引用的详细信息。

我发现在Rails（实际上是任何关系数据库）中将相关事物联系在一起的最好方法是在子表中将引用添加到父id。您可以在Rails中进行迁移。

rails g migration AddContestToSubmission contest:references

并修改db/migrate/<datetime>_add_contest_to_submission中生成的迁移文件，使其类似于：

class AddContestToSubmission < ActiveRecord::Migration
  def change
    add_reference :submissions, :contest, index: true
  end
end

然后继续查看submissions中的schema.rb表格。您应该注意到t.integer "contest_id"之类的内容您可能还应该在迁移中添加user_id，因为您希望将提交内容绑定到一个user。

Answer 2

我认为你让这有点复杂。

提交在比赛中张贴，提交需要知道user_id。

<%= simple_form_for :submission, url: contest_submissions_path(contest) do |f| %>
                  ...
    <%= f.submit 'Submit', class: "button" %>
<% end %>

并提交您的提交CREATE方法

class SubmissionsController < ApplicationController

  def create
    @contest = Contest.find(params[:contest_id])
    @submission = @contest.submissions.new(submission_params)
    @submissions.user = current_user
    .....
  end

魔术发生在@submissions.user = current_user如果你正在使用Devise，很容易传入控制器中的current_user.id ANYWHERE，正如我在提交控制器中所做的那样。

在rails中保存用户ID用户提交 - 竞赛有很多通过模型

2 个答案: