Question

我对python很新，并且在c ++中有一点背景。我只是想到了面向对象的编程，但是我在创建这个类中定义打印方法时遇到了问题。我已经阅读了repr（）和str（）函数，但它们似乎都不起作用。

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任何人都可以解释我如何创建一个方法，这样我就可以简单地打印有关该对象的信息（即peep.print_species =“Gallus Domesticus”）？

由于

Answer 1

您在函数调用结束时缺少括号。

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当您编写没有括号的peep.print_eatable() peep.print_species()时，Python不会报告语法错误，因为它是一个完全合法的语句，它返回方法对象peep.print_species。

Answer 2

您需要 CALL 您的方法，而不仅仅是获取它们。将print_species放在你的陈述后面：

()

Answer 3

您需要在函数调用结束时添加括号：

peep.print_eatable()
peep.print_species()

所以代码应该是：

class chicken():
    def __init__(self, name, eatable, species):
        self.name=name
        if eatable!="yes" and eatable!="no":
            self.eatable="no"
        else:
            self.eatable=eatable
        self.species=species
    #Print the species when called
    #Doesnt work for some reason
    def print_species(self):
        print"%s" %str(self.species)
    #Print whether or not the bird is eatable
    #This method also doesnt work
    def print_eatable(self):
        print "%s" %str(self.eatable)
    def change_species(self, new_name):
        self.species=new_name
    def change_eatable(self, new_status):
        self.eatable=new_status
        if new_status!="yes" and new_status!="no":
            self.eatable="no"
        else:
            self.eatable=new_status
peep=chicken("Peep", "yes", "Gallus Domesticus")
peep.change_eatable("meatballs")
peep.print_eatable()
peep.print_species()
#This does work
print peep.eatable

如何在Python中创建打印方法

3 个答案: