Google Maps和java.net.SocketTimeoutException:读取超时

时间:2015-06-25 15:29:03

标签: java google-maps google-geocoder google-geocoding-api socket-timeout-exception

以下代码有一些问题。首先,它给了我一个SocketTimeoutException。这几天前工作得很好,但现在却抛出了这个错误。我不确定如何将问题追溯到源头。我尝试增加超时(我真的认为最终不会起作用),但它总是在18秒后超时。更奇怪的是,当我尝试从其他东西(例如http://mysafeinfo.com/api/data?list=englishmonarchs&format=json)获取JSON文件时,URL可以正常工作。我等了大约一天,问题仍然存在。我能解决这个问题吗?

import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.net.URL;
import java.net.URLConnection;
import java.util.Timer;
import java.util.TimerTask;

import org.json.simple.JSONObject;
import org.json.simple.parser.JSONParser;

public class SocketTimeoutError {

    public static void main(String args[]) {
        URL myURL;
        TimerTask task = null;
        try {
            myURL = new URL(
                    "https://maps.googleapis.com/maps/api/geocode/json?address=Chicago+Illinois");

            URLConnection conn = myURL.openConnection();
            conn.connect();
            conn.setConnectTimeout(4 * 600000);
            conn.setReadTimeout(4 * 600000);
            //
            Timer timer = new Timer();
            task = new TimerTask() {
                int time = 0;

                public void run() {
                    System.out.println(time++);
                }
            };
            //
            System.out.println("Connecting..." + "Timeout="
                    + conn.getConnectTimeout());
            timer.scheduleAtFixedRate(task, 0, 1000);
            BufferedReader in = new BufferedReader(new InputStreamReader(
                    conn.getInputStream()));
            task.cancel();
            JSONParser parser = new JSONParser();
            JSONObject jsonObject = (JSONObject) parser.parse(in);
            String status = (String) jsonObject.get("status");
            System.out.println(status);

        } catch (Exception e) {
            e.printStackTrace();
            System.exit(-1);
        }
    }

}

这是我的控制台输出:

Connecting...Timeout=2400000
0
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
java.net.SocketTimeoutException: Read timed out
    at java.net.SocketInputStream.socketRead0(Native Method)
    at java.net.SocketInputStream.socketRead(Unknown Source)
    at java.net.SocketInputStream.read(Unknown Source)
    at java.net.SocketInputStream.read(Unknown Source)
    at sun.security.ssl.InputRecord.readFully(Unknown Source)
    at sun.security.ssl.InputRecord.read(Unknown Source)
    at sun.security.ssl.SSLSocketImpl.readRecord(Unknown Source)
    at sun.security.ssl.SSLSocketImpl.readDataRecord(Unknown Source)
    at sun.security.ssl.AppInputStream.read(Unknown Source)
    at java.io.BufferedInputStream.fill(Unknown Source)
    at java.io.BufferedInputStream.read1(Unknown Source)
    at java.io.BufferedInputStream.read(Unknown Source)
    at sun.net.www.http.HttpClient.parseHTTPHeader(Unknown Source)
    at sun.net.www.http.HttpClient.parseHTTP(Unknown Source)
    at sun.net.www.protocol.http.HttpURLConnection.getInputStream0(Unknown Source)
    at sun.net.www.protocol.http.HttpURLConnection.getInputStream(Unknown Source)
    at sun.net.www.protocol.https.HttpsURLConnectionImpl.getInputStream(Unknown Source)
    at SocketTimeoutError.main(SocketTimeoutError.java:38)

--- ---编辑 我一直在我的工作机器上这样做。我刚刚在我的家用电脑上试过这个代码,它运行得很好。此外,我工作的公司拥有Google for Work许可。我不明白公司和谷歌服务器之间的网络问题是什么,因为我可以在Chrome浏览器中查看json。

1 个答案:

答案 0 :(得分:1)

我已经弄清楚问题是什么。我不得不通过代理连接(我们的浏览器会自动执行此操作并解释我在使用Web浏览器时获得响应的原因)。我只需要通过以下方式修改我的代码:

Proxy proxy = new Proxy(Proxy.Type.HTTP, new InetSocketAddress("proxy.url.com", 80));
URLConnection myURLConnection = myURL.openConnection(proxy);