Question

我需要在Java代码中将2个字节（2的补码）转换为int。我该怎么做？

toInt(byte hb, byte lb)
{

}

Answer 1

return ((int)hb << 8) | ((int)lb & 0xFF);

所有情况下的正确操作都留给学生练习。

Answer 2

您还可以使用ByteBuffer类：

public int toInt(byte hb, byte lb) {
    ByteBuffer bb = ByteBuffer.wrap(new byte[] {hb, lb});
    return bb.getShort(); // Implicitly widened to an int per JVM spec.
}

如果要解码大量数据，此类可能会有所帮助。

Answer 3

<强>用法：

public class Test {

    public static void main(String[] args) {
        byte[] b = new byte[] { -83, 0, 0, 0 };

        int i = GattUtils.getIntValue(b, GattUtils.FORMAT_UINT32, 0);

        System.out.println(i); //will print 173
    }


public class GattUtils {
    public static final long leastSigBits = 0x800000805f9b34fbL;

    public static final int FIRST_BITMASK = 0x01;
    public static final int SECOND_BITMASK = FIRST_BITMASK << 1;
    public static final int THIRD_BITMASK = FIRST_BITMASK << 2;
    public static final int FOURTH_BITMASK = FIRST_BITMASK << 3;
    public static final int FIFTH_BITMASK = FIRST_BITMASK << 4;
    public static final int SIXTH_BITMASK = FIRST_BITMASK << 5;
    public static final int SEVENTH_BITMASK = FIRST_BITMASK << 6;
    public static final int EIGTH_BITMASK = FIRST_BITMASK << 7;

    public static final int FORMAT_UINT8 = 17;
    public static final int FORMAT_UINT16 = 18;
    public static final int FORMAT_UINT32 = 20;
    public static final int FORMAT_SINT8 = 33;
    public static final int FORMAT_SINT16 = 34;
    public static final int FORMAT_SINT32 = 36;
    public static final int FORMAT_SFLOAT = 50;
    public static final int FORMAT_FLOAT = 52;

    public static UUID toUuid(String uuidString) {
        return UUID.fromString(uuidString);
    }

    public static UUID toUuid(long assignedNumber) {
        return new UUID((assignedNumber << 32) | 0x1000, leastSigBits);
    }

    public static String toUuid128(long assignedNumber) {
        return toUuid(assignedNumber).toString();
    }

    public static String toUuid16(int assignedNumber) {
        return Integer.toHexString(assignedNumber);
    }

    public static Integer getIntValue(byte[] value, int format, int position) {
        if (value == null)
            return null;
        if (position + (format & 0xF) > value.length)
            return null;
        switch (format) {
        case FORMAT_UINT8:
            return Integer.valueOf(value[position] & 0xFF);
        case FORMAT_UINT16:
            return Integer.valueOf(add(value[position], value[(position + 1)]));
        case FORMAT_UINT32:
            return Integer.valueOf(add(value[position], value[(position + 1)], value[(position + 2)], value[(position + 3)]));
        case FORMAT_SINT8:
            return Integer.valueOf(signed(value[position] & 0xFF, 8));
        case FORMAT_SINT16:
            return Integer.valueOf(signed(add(value[position], value[(position + 1)]), 16));
        case FORMAT_SINT32:
            return Integer.valueOf(signed(add(value[position], value[(position + 1)], value[(position + 2)], value[(position + 3)]), 32));
        }
        return null;
    }

    public static Float getFloatValue(byte[] value, int format, int position) {
        if (value == null)
            return null;
        if (position + (format & 0xF) > value.length)
            return null;
        int i;
        int mantissa;
        int exponent;
        switch (format) {
        case FORMAT_SFLOAT:
            i = value[(position + 1)];
            position = value[position];
            mantissa = signed((position & 0xFF) + ((i & 0xFF & 0xF) << 8), 12);
            exponent = signed((i & 0xFF) >> 4, 4);
            return Float.valueOf((float) (mantissa * Math.pow(10.0D, exponent)));
        case FORMAT_FLOAT:
            exponent = value[(position + 3)];
            mantissa = value[(position + 2)];
            i = value[(position + 1)];
            position = value[position];
            return Float.valueOf((float) ((format = signed((position & 0xFF) + ((i & 0xFF) << 8) + ((mantissa & 0xFF) << 16), 24)) * Math.pow(10.0D, exponent)));
        }
        return null;
    }

    public static String getStringValue(byte[] value, int position) {
        if (value == null)
            return null;
        if (position > value.length)
            return null;
        byte[] arrayOfByte = new byte[value.length - position];
        for (int i = 0; i != value.length - position; i++) {
            arrayOfByte[i] = value[(position + i)];
        }
        return new String(arrayOfByte);
    }

    private static int add(byte byte1, byte byte2) {
        return (byte1 & 0xFF) + ((byte2 & 0xFF) << 8);
    }

    private static int add(byte byte1, byte byte2, byte byte3, byte byte4) {
        return (byte1 & 0xFF) + ((byte2 & 0xFF) << 8) + ((byte3 & 0xFF) << 16) + ((byte4 & 0xFF) << 24);
    }

    private static int signed(int value, int length) {
        if ((value & 1 << length - 1) != 0)
            value = -1 * ((1 << length - 1) - (value & (1 << length - 1) - 1));
        return value;
    }

    /**
     * Convert hex byte array from motorola API to byte array.
     * 
     * @param hexByteArray
     * @return
     */
    public static byte[] hexByteArrayToByteArray(byte[] hexByteArray) {
        return hexStringToByteArray(new String(hexByteArray));
    }

    /**
     * Convert string from motorola API to a byte array.
     * 
     * @param hexString
     * @return
     */
    public static byte[] hexStringToByteArray(String hexString) {
        int len = hexString.length();
        byte[] data = new byte[len / 2];
        for (int i = 0; i < len; i += 2) {
            data[i / 2] = (byte) ((Character.digit(hexString.charAt(i), 16) << 4) + Character.digit(hexString.charAt(i + 1), 16));
        }
        return data;
    }
}

Answer 4

public int toInt(byte hb, byte lb)
{
    return ((int)hb)<<8 + lb;
}

Answer 5

对于那些正在寻找Little Endian值的人：

int num = ByteBuffer.wrap(b, 0, 2).order(LITTLE_ENDIAN).char.toInt()

在Java中将字节转换为int

5 个答案: