这是我的数据,Json_encode()
之后
Array
(
[{"customerId":"1","customer_name":"Jon_doe","amount":"12312312","billcode":"b1231","billname":"cashbilname","billcategorycode":"1234","billcategory":"utility","month":"May","year":"2015","txcode":"10","stationid":"152","station":"Coroom","operatorcode":"1200","operator":"jame","terminal":"ter12312","txdate":"12\/2\/2015","txtime":"12:21:22_PM"}]
=>
)
现在我想要解码它,通过应用json_decode()
它会出现以下错误
json_decode()期望参数1为字符串,给定数组
有什么想法可以做什么?
答案 0 :(得分:5)
您的json
必须位于string
,而不是array
$json_string = '{"a":1,"b":2,"c":3,"d":4,"e":5}';
$json_array = json_decode($json_string);
$json_array : array('a' => 1, 'b' => 2, 'c' => 3, 'd' => 4, 'e' => 5);
如果json
位于array
,您可以执行以下操作:
$json_string_in_array = array('{"a":1,"b":2,"c":3,"d":4,"e":5}');
$json_array = json_decode($json_string_in_array[0]);
答案 1 :(得分:2)
json_encode()返回一个字符串,所以我不知道如何从中获取数组,除非你自己将它存储在数组中:
$json = [];
$json[] = json_encode($someArray);
相反,只需将其存储在非数组变量中:
$jsonString = json_encode($someArray);
然后你可以像这样解码它:
$decodedArray = json_decode($jsonString);
答案 2 :(得分:0)
SCNu32