我想复制新列中的所有行,并用 - 替换所有特殊字符。我的代码如下。
我的桌面设计
select * from mycode
UPDATE mycode
SET newName = Replace(myname, '%[^0-9a-zA-Z]%', '-')
我的代码正在复制,但不会替换特殊字符
结果
答案 0 :(得分:5)
尝试创建此功能
runApp("dir")
然后执行create function dbo.RemoveSpecialChars (@s varchar(256)) returns varchar(256)
with schemabinding
begin
if @s is null
return null
declare @s2 varchar(256)
set @s2 = ''
declare @l int
set @l = len(@s)
declare @p int
set @p = 1
while @p <= @l begin
declare @c int
set @c = ascii(substring(@s, @p, 1))
if @c between 48 and 57 or @c between 65 and 90 or @c between 97 and 122
set @s2 = @s2 + char(@c)
set @p = @p + 1
end
if len(@s2) = 0
return null
return @s2
end
UPDATE
答案 1 :(得分:5)
尝试此查询
DECLARE @specialchar varchar(15)
DECLARE @getspecialchar CURSOR
SET @getspecialchar = CURSOR FOR
SELECT DISTINCT poschar
FROM MASTER..spt_values S
CROSS APPLY (SELECT SUBSTRING(newName ,NUMBER,1) AS poschar from mycode ) t
WHERE NUMBER > 0
AND NOT (ASCII(t.poschar) BETWEEN 65 AND 90
OR ASCII(t.poschar) BETWEEN 97 AND 122
OR ASCII(t.poschar) BETWEEN 48 AND 57)
OPEN @getspecialchar
FETCH NEXT
FROM @getspecialchar INTO @specialchar
WHILE @@FETCH_STATUS = 0
BEGIN
UPDATE mycode
SET newName =Replace(myname,@specialchar,'')
FETCH NEXT
FROM @getspecialchar INTO @specialchar
END
CLOSE @getspecialchar
DEALLOCATE @getspecialchar