Question

我有一个ul li列表，可以选择对元素进行排序和上下移动。我的要求是，一旦用户以所需的方式对元素进行排序，我希望能够将该序列保存在数据库中。

我是否可以获得一个包含li标识的数组以及li的位置索引。

例如。在这种情况下，当值= 9时，索引应为0，
value = 11，index = 1等。

渲染的示例html是：

 <ul id="ul_li_SubCategories" style="width:200px;" class="chargeCapturetable margin0">
    <li sequence="1" title="Category 1" class="liEllipsis" value="9"><a href="#"><span class="viewIcons delFaceName _delete fl"></span>Category 1</a></li>
    <li sequence="2" title="Category 3" class="liEllipsis" value="11"><a href="#"><span class="viewIcons delFaceName _delete fl"></span>Category 3</a></li>
    <li sequence="4" title="Category 4" class="liEllipsis" value="12"><a href="#"><span class="viewIcons delFaceName _delete fl"></span>Category 4</a></li>
    <li sequence="5" title="Category 6" class="liEllipsis" value="22"><a href="#"><span class="viewIcons delFaceName _delete fl"></span>Category 6</a></li>
    <li sequence="6" title="Category 5" class="liEllipsis" value="13"><a href="#"><span class="viewIcons delFaceName _delete fl"></span>Category 5</a></li>
    <li sequence="7" title="Category 7" class="liEllipsis" value="55"><a href="#"><span class="viewIcons delFaceName _delete fl"></span>Category 7</a></li>
    <li sequence="99999" title="Category 8" class="liEllipsis" value="62"><a href="#"><span class="viewIcons delFaceName _delete fl"></span>Category 8</a></li>
</ul>

Answer 1

获取一个数组，其中包含li的ID和li的位置索引。

.map()可与.attr()

一起使用

var arr = $('#ul_li_SubCategories li').map(function (elem) {
    return {
        value : $(this).attr('value'),
        index : $(this).index()
    }
}).get();

$(function() {
  var arr = $('#ul_li_SubCategories li').map(function(elem) {
    return {
      value: $(this).attr('value'),
      index: $(this).index()
    }
  }).get();
  
  console.log(arr)
});

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<ul id="ul_li_SubCategories" style="width:200px;" class="chargeCapturetable margin0">
  <li sequence="1" title="Category 1" class="liEllipsis" value="9"><a href="#"><span class="viewIcons delFaceName _delete fl"></span>Category 1</a>
  </li>
  <li sequence="2" title="Category 3" class="liEllipsis" value="11"><a href="#"><span class="viewIcons delFaceName _delete fl"></span>Category 3</a>
  </li>
  <li sequence="4" title="Category 4" class="liEllipsis" value="12"><a href="#"><span class="viewIcons delFaceName _delete fl"></span>Category 4</a>
  </li>
  <li sequence="5" title="Category 6" class="liEllipsis" value="22"><a href="#"><span class="viewIcons delFaceName _delete fl"></span>Category 6</a>
  </li>
  <li sequence="6" title="Category 5" class="liEllipsis" value="13"><a href="#"><span class="viewIcons delFaceName _delete fl"></span>Category 5</a>
  </li>
  <li sequence="7" title="Category 7" class="liEllipsis" value="55"><a href="#"><span class="viewIcons delFaceName _delete fl"></span>Category 7</a>
  </li>
  <li sequence="99999" title="Category 8" class="liEllipsis" value="62"><a href="#"><span class="viewIcons delFaceName _delete fl"></span>Category 8</a>
  </li>
</ul>

Answer 2

How do I iterate through child elements of a div using jQuery?

这应该指向正确的方向。只需将div替换为有问题的ul ...

或者，在jsFiddle中编写代码...... http://jsfiddle.net/

Answer 3

使用此：

 [9, 11, 12, 22, 13, 55, 62]

输出：

df = pd.DataFrame({
        'A':
            ['1980-01-01', '1980-02-02', '1980-03-02', '1980-01-21',
             '1981-01-21', '1991-02-21', '1991-03-23'] })
df['A'] = pd.to_datetime(df['A']).astype('int64')
max_a = df.A.max()
min_a = df.A.min()
min_norm = -1
max_norm =1
df['NORMA'] = (df.A- min_a) *(max_norm - min_norm) / (max_a-min_a) + min_norm

Answer 4

首先，您需要获取每个值，然后您需要构建数组并将其序列化，最后您可以使用Ajax调用来保存它。这是JSFiddle complete

$(document).ready(function() {
    var items = [];

    $('#ul_li_SubCategories > li').each(function () {
        items.push({
            value : $(this).attr('value'),
            index : $(this).index()
        });
    });

    $.ajax({
        url: "your url to save the items",
        type: "POST",
        data: items,
        success:function(result){
            alert(result);
        },
        error:function(xhr,status,error){
            alert(status);
        }
    });
});

Answer 5

参考以下答案

    
    $(function(){

$('.glyphicon-arrow-up').on('click', function(e){
   e.preventDefault();
    var _this = $(this);
    var _parent = _this.closest('ul');
    var _child = $(_parent).find('li');
    var selected= $(this).closest('li').index();
    jQuery($(_parent).children().eq(selected-1)).before(jQuery($(_parent).children().eq(selected)));

    var _child = _this.closest('ul').children();
    var _childLength = _child.length;

    var input = Array();
    $.each(_child, function(key, val){
        input[key] = $(val).data('id');
    })
     // Use below if required to update into database
    $.ajax({
        url: 'ajax.php',
        data:{
            'inputArray':input,
            'queryString':'updatePrecedence',
        },
        type: "POST",
        dataType : 'JSON',
        success: function(data){
        }
    });
});

$('.glyphicon-arrow-down').on('click', function(e){
   e.preventDefault();
    var _this = $(this);
    var _parent = _this.closest('ul');
    var _child = $(_parent).find('li');
    var selected= $(this).closest('li').index();

    jQuery($(_parent).children().eq(selected+1)).after(jQuery($(_parent).children().eq(selected)));
    selected=selected+1;

    var _child = _this.closest('ul').children();
    var _childLength = _child.length;

    var input = Array();
    $.each(_child, function(key, val){
        input[key] = $(val).data('id');
    })

   // Use below if required to update into database
    $.ajax({
        url: 'ajax.php',
        data:{
            'inputArray':input,
            'queryString':'updatePrecedence',
        },
        type: "POST",
        dataType : 'JSON',
        success: function(data){
        }
    });

});

})

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<ul>
	<li>Sample 1 <span class="glyphicon-arrow-up">Up</span><span class="glyphicon-arrow-down">Down</span></li>
	<li>Sample 2 <span class="glyphicon-arrow-up">Up</span><span class="glyphicon-arrow-down">Down</span></li>
	<li>Sample 3 <span class="glyphicon-arrow-up">Up</span><span class="glyphicon-arrow-down">Down</span></li>
	<li>Sample 4 <span class="glyphicon-arrow-up">Up</span><span class="glyphicon-arrow-down">Down</span></li>
	<li>Sample 5 <span class="glyphicon-arrow-up">Up</span><span class="glyphicon-arrow-down">Down</span></li>
	<li>Sample 6 <span class="glyphicon-arrow-up">Up</span><span class="glyphicon-arrow-down">Down</span></li>
	<li>Sample 7 <span class="glyphicon-arrow-up">Up</span><span class="glyphicon-arrow-down">Down</span></li>
</ul>

您将在以下行

之后获得索引值

var input = Array();
    $.each(_child, function(key, val){
        input[key] = $(val).data('id');
    })

如果您打印console.log(input)，您将获得数组索引

保持Ul Li列表的序列

5 个答案: