Question

我有这个代码，我试图从这个JSON字符串中获取项目，但它失败了。

我正在从远程主机解析Json字符串。

package selectDB;

import java.io.*;
import java.net.URL;
import java.net.URLConnection;
import java.sql.*;
import java.text.DateFormat;
import java.text.SimpleDateFormat;
import java.util.Date;
import java.util.Timer;
import java.util.TimerTask;
import org.json.simple.*;

public class selectDB
 {
  public static void main(String[] args) throws IOException, ParseException
  {
      String s = "";
      URL u = new URL("http://192.168.3.1/android/select.php");
      URLConnection c = u.openConnection();
      InputStream r = c.getInputStream();
      BufferedReader reader = new BufferedReader(new InputStreamReader(r));
      for(String line; (line = reader.readLine()) != null;)
          {
            s+=line;
          }
      System.out.println(s);
  }
}

结果是

{"result" : "true" , "messages" : [{"id":"866343023633578","latitute":"27","longitude":"31","number_phone":"01113171374"},{"id":"352168066354050","latitute":"27","longitude":"31","number_phone":"202222"},{"id":"50","latitute":"50","longitude":"100","number_phone":"50"},{"id":"110","latitute":"50","longitude":"50","number_phone":"110"},{"id":"120","latitute":"27","longitude":"31","number_phone":"120"},{"id":"130","latitute":"28","longitude":"29","number_phone":"120"},{"id":"140","latitute":"30","longitude":"40","number_phone":"140"},{"id":"800","latitute":"60","longitude":"30","number_phone":"800"},{"id":"353629054230064","latitute":"70","longitude":"80","number_phone":"120"}]}

请帮忙！

Answer 1

你可以使用JsonReader类。

try (JsonReader in = Json.createReader(r)) {

      JsonObject jsonObject= in.readObject();
      YourObject obj = new YourObject();
      obj.setSomething(jsonObject.getString("something", null));

      // "something" is the key in the json file, null is the default
      // when "something" was not found      

} catch (JsonException | ClassCastException ex) {
      throw new BadRequestException("Invalid Json Input");
}

Answer 2

您也可以使用Google图书馆GSON，它易于使用和自我解释。

https://code.google.com/p/google-gson/

Gson Goals

提供简单的toJson（）和fromJson（）方法，将Java对象转换为JSON，反之亦然       允许将预先存在的不可修改对象转换为JSON和从JSON转换       广泛支持Java Generics       允许对象的自定义表示       支持任意复杂的对象（具有深层继承层次结构和广泛使用泛型类型）

如何从Java中解析JSON字符串中的项目

2 个答案: