PHP Preg替换以删除部分字符串

Question

我想使用preg_replace从字符串中删除一个部分，我搜索了很长时间，但我找不到一种方法来帮助我做出正确的表达。 字符串：

test test test test test test test test test test test test test test     test test test test test test test test test test
<div>[[{"fid":"1915134","view_mode":"default","type":"media","attributes": {"height":360,"width":480,"alt":"#some text here","class":"media-element file-default"}}]]</div>
test test test test test test test test test test test test test testtest test test test test test test test test test
test test test test test test test test test test test test

从[[{"fid":"开始删除部件，然后以}}]]

结束

Answer 1

您可以使用：

$a = preg_replace('/\[\[{"fid"[^}\]]+}}\]\]/','',$a);