如何在mysql中搜索匹配的charecter

Question

$result = mysqli_query($conn, "SELECT * FROM ProcessTrackingSystem.ProcessDetails WHERE Sample_name LIKE '$userinput' OR Client_name LIKE '$userinput1%'") or die(mysqli_error($conn));  

我正在尝试执行上面的查询，但是它从mysql数据库输出完整的详细信息。

如何解决这个问题？
提前谢谢!!

Answer 1

缺少/usr/include/sys -

cdefs.h

Check the docs

Answer 2

你必须使用＆＃39;％＆＃39;运营商。 Like总是期望%。试试这个 -

$result = mysqli_query($conn, "SELECT * FROM ProcessTrackingSystem.ProcessDetails WHERE Sample_name LIKE '%$userinput'") or die(mysqli_error($conn));  

Answer 3

您错过了%登录$userinput

$result = mysqli_query($conn, "SELECT * FROM ProcessTrackingSystem.ProcessDetails WHERE Sample_name LIKE '%$userinput%'") or die(mysqli_error($conn));