Question

https://support.google.com/analytics/answer/1257084?hl=en-GB#pageviews_vs_unique_views

我正在尝试计算Google Analytics在其界面上每天唯一网页浏览量的总和如何使用bigquery获得等效项？

Answer 1

使用它的方法有两种：

1）正如原始链接文档所说的那样，要结合完整的访问者用户ID和他们不同的会话ID：visitId，并计算这些。

SELECT
  EXACT_COUNT_DISTINCT(combinedVisitorId)
FROM (
  SELECT
    CONCAT(fullVisitorId,string(VisitId)) AS combinedVisitorId
  FROM
    [google.com:analytics-bigquery:LondonCycleHelmet.ga_sessions_20130910]
  WHERE
    hits.type='PAGE' )

2）另一个只计算不同的fullVisitorIds

SELECT
  EXACT_COUNT_DISTINCT(fullVisitorId)
FROM
  [google.com:analytics-bigquery:LondonCycleHelmet.ga_sessions_20130910]
WHERE
  hits.type='PAGE'

如果有人想在样本公共数据集上尝试此操作，则会有tutorial how to add the sample dataset。

Answer 2

其他查询与我的Google Analytics帐户中的“唯一身份浏览量”指标不匹配，但以下情况确实如下：

SELECT COUNT(1) as unique_pageviews
FROM (
    SELECT 
        hits.page.pagePath, 
        hits.page.pageTitle,
        fullVisitorId,
        visitNumber,
        COUNT(1) as hits
    FROM [my_table]
    WHERE hits.type='PAGE' 
    GROUP BY 
        hits.page.pagePath, 
        hits.page.pageTitle,
        fullVisitorId,
        visitNumber
)

Answer 3

对于uniquePageViews，你最好使用这样的东西：

SELECT
  date,
  SUM(uniquePageviews) AS uniquePageviews
FROM (
  SELECT
    date,
    CONCAT(fullVisitorId,string(VisitId)) AS combinedVisitorId,
    EXACT_COUNT_DISTINCT(hits.page.pagePath) AS uniquePageviews
  FROM
    [google.com:analytics-bigquery:LondonCycleHelmet.ga_sessions_20130910]
  WHERE
    hits.type='PAGE'
  GROUP BY 1,2)
GROUP EACH BY 1;

如何在Bigquery中获取唯一网页浏览量的Google Analytics定义

3 个答案: