Question

我制作了一个非常简单的Swift应用程序，它加载了一个带有链接的网页。每当我点击链接时，它们都不会打开。如何在OS X的浏览器窗口中打开已加载的.html网页上的链接？

这是我的实施：

import Cocoa
import WebKit

class ViewController: NSViewController {

    @IBOutlet weak var webView: WebView!

    override func viewDidLoad() {
        super.viewDidLoad()
        let urlString = "URL"
        self.webView.mainFrame.loadRequest(NSURLRequest(URL: NSURL(string: urlString)!))
    }

    override var representedObject: AnyObject? {
        didSet {
            // Update the view, if already loaded.
        }
    }
}

Answer 1

首先，将WebView的策略委托和初始URL设置为类变量：

let url = NSURL(string: "http://www.google.com/")!

// ...

override func viewDidLoad() {
    super.viewDidLoad()

    // Do any additional setup after loading the view.

    self.webView.policyDelegate = self

    self.webView.mainFrame.loadRequest(NSURLRequest(URL: self.url))
}

然后，覆盖委托方法以拦截导航。

override func webView(webView: WebView!, decidePolicyForNewWindowAction actionInformation: [NSObject : AnyObject]!, request: NSURLRequest!, newFrameName frameName: String!, decisionListener listener: WebPolicyDecisionListener!) {
    println(__LINE__) // the method is needed, the println is for debugging
}


override func webView(webView: WebView!, decidePolicyForNavigationAction actionInformation: [NSObject : AnyObject]!, request: NSURLRequest!, frame: WebFrame!, decisionListener listener: WebPolicyDecisionListener!) {
    if request.URL!.absoluteString == self.url.absoluteString { // load the initial page
        listener.use() // load the page in the app
    } else { // all other links
        NSWorkspace.sharedWorkspace().openURL(request.URL!) // take the user out of the app and into their default browser
    }
}

Answer 2

您还可以决定在WebView中打开哪些链接以及在浏览器中使用哪种链接就像在HTML页面中编写目标属性一样简单

<a href="http://www.google.com/" target="_blank">external page</a>

并在上面提到的decisionPolicyForNewWindowAction中使用目标检查。我在this question帖子中给出了完整的答案。希望你能把它翻译成快速的。

在浏览器中打开WebView URL

2 个答案: