如何获取我自己的号码来检查宾果游戏的随机数

时间:2015-06-24 15:43:33

标签: c#

我的宾果游戏应该非常简单,你从1 - 25写下10个数字,它应该取出7个随机数与我自己的10个数字进行比较,最后我希望它能显示结果。

我被numbers == bingorow搞砸了。如何检查我有多少权利?这是我的代码:

static void Main(string[] args)
{
    int right = 0;
    bool foundNr = false;
    int[] bingorow = new int[11];
    for (int i = 0; i < bingorow.Length; i++)
    {
        try
        {
            Console.WriteLine("Welcome to C Sharp Bingo!");
            Console.Write("Write down 10 numbers here: ");
            int bingonr = int.Parse(Console.ReadLine());
            bingorow[i] = bingonr;
        }
        catch
        {
            Console.WriteLine("Please write 10 numbers!");
            continue;
        }

        int[] number = new int[7];
        Random randmNr = new Random();
        for (int r = 0; r < number.Length; r++)
        {
            number[r] = randmNr.Next(1, 25);
        }

        if (number == bingorow)
        {
            foundNr = true;
        }

        if (foundNr == true)
        {
            right++;
        }
        {
            Console.WriteLine("  Your score: {0} of 7", right);
            Console.ReadLine();
        }
    }
}

2 个答案:

答案 0 :(得分:1)

这是一个草率的答案,但它可能会帮助您解决问题。

首先,无论try / catch块是否失败,你的for循环都会运行 11 次。

int[] bingorow = new int[11];
for (int i = 0; i < bingorow.Length; i++)

其次,当您从捕获中“继续”时,您基本上会打印一条消息并继续执行该程序。我建议抛出一个适当的例外。

第三,回到for循环 - 程序将接受一个值,然后运行所有代码。所以基本上如果你幸运,你会猜到7分中的1分。然后循环将再次运行第二次,你会得到另一个数字......等等。这就是为什么我在循环外捕获后的所有代码。这样它将迭代多次(在这种情况下为7)并从每次迭代的输入中获得一个数字。在存储了所有7个数字之后,它将继续执行其余的代码。

第四,不确定您是否希望数字在1-25范围内。

number[r] = randmNr.Next(1, 25);

这将返回1-24范围内的数字,因为Next方法的上限是独占的,正如Mark在此处所述:https://stackoverflow.com/a/5063276/4453195

以下是您问题的简单解决方案:

static void Main(string[] args)
{
    int right = 0;
    int[] bingorow = new int[7]; // Correct me if I'm wrong but I think a 7 number bingo should accept 7 numbers as input
    string[] positions = { "first", "second", "third", "fourth", "fifth", "sixth", "seventh" }; // This is not necessary, but makes the flow slightly clearer.

    Console.WriteLine("#########################");
    Console.WriteLine("Welcome to C Sharp Bingo!");
    Console.WriteLine("#########################");
    Console.WriteLine("Please provide your 7 numbers in the range from 1 to 25.");

    for (int i = 0; i < bingorow.Length; i++)
    {
        try
        {
            Console.WriteLine("Enter your {0} number:", positions[i]);
            int bingonr = int.Parse(Console.ReadLine());
            bingorow[i] = bingonr;
        }

        catch
        {
            Console.WriteLine("Some error message.");
            // Some Exception should be thrown here don't just use "continue".
            continue;
        }
    }

   int[] numbers = new int[7];
   Random randmNr = new Random();
   for (int r = 0; r < numbers.Length; r++)
   {
       // randmNr.Next(1, 26) will return numbers in the range 1-25 inclusive.
       numbers[r] = randmNr.Next(1, 26);
   }

   // Loop through each number from the input (bingorow) array and check if it is contained in the "winning" (numbers) array
   for (int i = 0; i < bingorow.Length; i++)
   {
       if (numbers.Contains(bingorow[i]))
       {
           right++; // Increment counter on each match.
       }
   }

   {
       Console.WriteLine();
       Console.WriteLine("### Your score: {0} of 7 ###", right);
       Console.Write("Your numbers:");

       // Print the input numbers.
       foreach (int number in bingorow)
       {
           Console.Write(" {0}", number); // Will not be sorted.
       }

       Console.WriteLine();

       Console.Write("Winning numbers:");

       // Print the winning numbers.
       foreach (int number in numbers)
       {
           Console.Write(" {0}", number); // Will not be sorted.
       }

       Console.WriteLine();

       Console.WriteLine("Press Enter to exit.");
       Console.ReadLine();
   }
}

答案 1 :(得分:0)

您不能只通过arr1 == arr2比较两个数组。在c#中,数组是对不同对象的引用。

int arr1[] = new int[] {1, 2, 3};
int arr2[] = new int[] {1, 2, 3};
if (arr1 == arr2) // Same as arr1.equals(arr2)
    Console.WriteLine("Same");
else
    Console.WriteLine("Not same"); //Will print not same.

.Net提供了许多不同的方法来比较数组和列表结构。对于.NET 4.0及更高版本,可以使用Structural Comparisons。否则将使用更简单的版本:

int arr1[] = new int[] {1, 2, 3};
int arr2[] = new int[] {1, 2, 3};
Console.WriteLine(arr1.SequenceEqual(arr2)); //Done using Linq.

number == bingorow更改为number.SequenceEqual(bingorow)以检查阵列本身是否相等。如果您正在寻找正确的单个元素,那么您需要执行嵌套循环或某种形式的for循环来检查数组中的每个单独的值。

前:

for( int i = 0; i < arr1.length; i++) //or whichever array is shorter
    if(arr1[i] == arr2[i])
       //true
    //else false