Question

我有3张桌子：

团队（id_team，name，id_season）
Teams_Stats（id_stats，id_game，id_team，胜利，失败）
季节（id_season，name，nbr_teams）

我试图为每个球队取得特定赛季的胜利数量（本例中为2015年）。

这就是我目前所拥有的，但它为所有球队返回0。

我的SQL语法：

SELECT T.name, count(a.victory) as Wins
FROM Teams T, Seasons S
  LEFT JOIN 
    (SELECT TS.id_team, TS.victory FROM Teams_Stats TS WHERE TS.victory = 1) a
  ON a.id_team = 'T.id_team'
WHERE T.id_season = S.id_season AND S.name = '2015'
GROUP BY T.nom 
ORDER BY T.nom

我做错了什么？

谢谢：）

Answer 1

尝试修改您的查询有点像

SELECT T.name, count(TS.victory) as Wins
FROM Teams T
JOIN Seasons S ON T.id_season = S.id_season AND S.name = '2015'
LEFT JOIN Teams_Stats TS ON TS.id_team = T.id_team AND TS.victory = 1
GROUP BY T.name 
ORDER BY T.name

MySQL count（col）返回null

1 个答案: