在PowerShell中,我知道如何发送基本电子邮件。但是使用下面的语法,我怎样才能将每个$QueryName
和每个$RowCount
添加到电子邮件的正文中,并添加指向$FPath\$FormattedDate\
中包含的值的超链接,以便电子邮件的正文看起来像像这样:
$QueryName - $RowCount
(或实际数据)
Santa - 14
Mickey - 12
Mars - 2
这是我目前的PS脚本
Function Execute-SQLquery {
param ($QueryName, $QueryString)
$server = "Server"
$database = "DB1"
$FPath = "C:\Testing"
#Setting additional variables
$extension = ".csv"
$date = Get-Date -f 'MM.dd.yy'
$FormattedDate = Get-Date -f 'MM.dd.yy'
$connectionTemplate = "Data Source={0};Integrated Security=SSPI;Initial Catalog={1};"
$connectionString = [string]::Format($connectionTemplate, $server, $database)
$connection = New-Object System.Data.SqlClient.SqlConnection
$connection.ConnectionString = $connectionString
$command = New-Object System.Data.SqlClient.SqlCommand
$command.CommandText = $QueryString
$command.Connection = $connection
$SqlAdapter = New-Object System.Data.SqlClient.SqlDataAdapter
$SqlAdapter.SelectCommand = $command
$DataSet = New-Object System.Data.DataSet
$rowCount = $SqlAdapter.Fill($DataSet)
if(!(Test-Path -path "$FPath\$FormattedDate\")){New-Item "$FPath\$FormattedDate\" -type directory}
if ($rowCount -gt 0)
{
if ($QueryName -eq "Santa")
{
$extractFile = "C:\Testing\TemplateFiles\Santa.csv"
[System.IO.Directory]::CreateDirectory("$FPath\$FormattedDate\Santa\")
Write-Host $rowCount -fore Red
$dirName = "$FPath\$FormattedDate\Santa\"
$filename = [IO.Path]::GetFileNameWithoutExtension($extractFile) + "_$date" + [IO.Path]::GetExtension($extractFile)
$extractFile = Join-Path $dirname $filename
}
if ($QueryName -eq "Mickey")
{
$extractFile = "C:\Testing\TemplateFiles\Mickey.csv"
[System.IO.Directory]::CreateDirectory("$FPath\$FormattedDate\Mickey\")
Write-Host $rowCount -fore Red
$dirName = "$FPath\$FormattedDate\Mickey\"
$filename = [IO.Path]::GetFileNameWithoutExtension($extractFile) + "_$date" + [IO.Path]::GetExtension($extractFile)
$extractFile = Join-Path $dirname $filename
}
if ($QueryName -eq "Mars")
{
$extractFile = "C:\Testing\TemplateFiles\Mickey\Mars.csv"
[System.IO.Directory]::CreateDirectory("$FPath\$FormattedDate\Mars\")
Write-Host $rowCount -fore Red
$dirName = "$FPath\$FormattedDate\Mars\"
$filename = [IO.Path]::GetFileNameWithoutExtension($extractFile) + "_$date" + [IO.Path]::GetExtension($extractFile)
$extractFile = Join-Path $dirname $filename
}
$DataSet.Tables[0] | Export-Csv $extractFile -NoTypeInformation
}
$connection.Close()
}
答案 0 :(得分:1)
首先,由于基于$QueryName
的唯一更改是直接引用$QueryName
和$extractFile
中的值,因此最好不要重复整个街区。
对于邮件消息,您可以使用Send-MailMessage
。
要添加指向本地文件资源的链接,请使用file:///
方案前缀并将所有反斜杠(\
)更改为正斜杠(/
),即。 file:///C:/Document/Path.ext
或您的示例"file:///$("$FPath\$FormattedDate" -replace '\','/')"
:
Function Execute-SQLquery {
param ($QueryName, $QueryString)
# up to this point no change is required
if ($rowCount -gt 0)
{
$extractFile = switch($QueryName){
"Santa" { "C:\Testing\TemplateFiles\Santa.csv" }
"Mickey" { "C:\Testing\TemplateFiles\Mickey.csv" }
"Mars" { "C:\Testing\TemplateFiles\Mars\Mickey.csv" }
default { throw "Illegal QueryName" }
}
[System.IO.Directory]::CreateDirectory("$FPath\$FormattedDate\$QueryName\")
Write-Host $rowCount -fore Red
$dirName = "$FPath\$FormattedDate\$QueryName\"
$filename = [IO.Path]::GetFileNameWithoutExtension($extractFile) + "_$date" + [IO.Path]::GetExtension($extractFile)
$extractFile = Join-Path $dirname $filename
$DataSet.Tables[0] | Export-Csv $extractFile -NoTypeInformation
$EmailBody = @'
Here are the results:
{0} - {1}
Find the documents <a href="file:///{2}">here</a>
'@ -f $QueryName,$rowCount,$("$FPath\$FormattedDate" -replace '\','/')
Send-MailMessage -From "me@company.example" -To "you@company.example" -Body $EmailBody -BodyAsHtml:$true -Subject "Data extracted!" -SmtpServer "your.mail.server.company.example"
}
$connection.Close()
}