下面我有一个来自c ++的代码片段。 我需要返回指针数组(到TempStruct)。
问题是在c#侧我只得到一个元素。另一方面,我得到AV。
**C++**
extern "C" __declspec(dllexport) void GetResult(TempStruct** outPtr, long *size)
{
*outPtr = (TempStruct*)new TempStruct*[2];
outPtr[0] = new TempStruct("sdf", 123);
outPtr[1] = new TempStruct("abc", 456);
*size = 2;
}
**C#**
[DllImport("test.dll", CallingConvention = CallingConvention.Cdecl, CharSet = CharSet.Ansi)]
public static extern void GetResult(out IntPtr outPtr, out int size);
IntPtr ptr = IntPtr.Zero;
int length;
GetResult(out ptr, out length);
int size = Marshal.SizeOf(typeof(TempStruct));
TempStruct[] someData2 = new TempStruct[length];
for (int i = 0; i < length; i++)
{
IntPtr wskptr = (IntPtr)(ptr.ToInt64() + (size * i));
someData2[i] = (TempStruct)Marshal.PtrToStructure(wskptr, typeof(TempStruct));
}
答案 0 :(得分:3)
你做错了。
您正在混合指针类型。
使用new TempStruct()
创建一个指向TempStruct
的指针数组。我给你的例子创建了一个TempStruct
数组。看到区别?
现在...... TempStruct** outPtr
应为TempStruct*** outPtr
(因为您想返回(*
)指针数组(*
)(*
) ...或TempStruct**&
如果您愿意: - )
更改此行
someData2[i] = (TempStruct)Marshal.PtrToStructure(Marshal.ReadIntPtr(wskptr), typeof(TempStruct));
因为你必须阅读单指针。
我希望您删除带有删除的各种TempStruct
并使用
delete[] ptr;
运算符删除结构数组。
完整示例:
C ++:
struct TempStruct
{
char* str;
int num;
// Note the strdup. You don't know the source of str.
// For example if the source is "Foo", then you can't free it.
// Using strdup solves this problem.
TempStruct(const char *str, int num)
: str(strdup(str)), num(num)
{
}
~TempStruct()
{
free(str);
}
};
extern "C"
{
__declspec(dllexport) void GetResult(TempStruct ***outPtr, int *size)
{
*outPtr = new TempStruct*[2];
(*outPtr)[0] = new TempStruct("sdf", 123);
(*outPtr)[1] = new TempStruct("abc", 456);
*size = 2;
}
__declspec(dllexport) void FreeSomeData(TempStruct **ptr, int size)
{
for (int i = 0; i < size; i++)
{
delete ptr[i];
}
delete[] ptr;
}
}
C#:
[StructLayout(LayoutKind.Sequential, CharSet = CharSet.Ansi, Pack = 1), Serializable]
internal struct TempStruct
{
public string str;
public int num;
}
[DllImport("NativeLibrary.dll", CallingConvention = CallingConvention.Cdecl, CharSet = CharSet.Ansi)]
static extern void GetResult(out IntPtr outPtr, out int numPtr);
[DllImport("NativeLibrary.dll", CallingConvention = CallingConvention.Cdecl)]
static extern void FreeSomeData(IntPtr ptr, int num);
// C++ will return its TempStruct array in ptr
IntPtr ptr;
int size;
GetResult(out ptr, out size);
TempStruct[] someData2 = new TempStruct[size];
for (int i = 0; i < size; i++)
{
IntPtr ptr2 = Marshal.ReadIntPtr(ptr, i * IntPtr.Size);
someData2[i] = (TempStruct)Marshal.PtrToStructure(ptr2, typeof(TempStruct));
}
// Important! We free the TempStruct allocated by C++. We let the
// C++ do it, because it knows how to do it.
FreeSomeData(ptr, size);
请注意,C#[Serializable]
Pack=1
和struct
更适合C ++:
__declspec(dllexport) void GetResult(TempStruct **&outPtr, int &size)
{
outPtr = new TempStruct*[2];
outPtr[0] = new TempStruct("sdf", 123);
outPtr[1] = new TempStruct("abc", 456);
size = 2;
}
更正确,因为outPtr
和size
都不能是NULL
。见https://stackoverflow.com/a/620634/613130。 C#签名是一样的。
答案 1 :(得分:3)
C ++代码错误。它返回一个指向struct的指针数组。您转换new
返回的值的事实应该提醒您错误的事实。您想要返回一个struct数组。
应该是:
*outPtr = new TempStruct[2];
(*outPtr)[0].str = "sdf";
(*outPtr)[0].i = 123;
(*outPtr)[1].str = "abc";
(*outPtr)[1].i = 456;
*size = 2;