Question

php error重复输入＆＃39; 0＆＃39;对于第1行的密钥1

include ("connect.php");
include ("register.php");

$urlIdd = isset($_POST['$urlId']);
$urlnamee = isset($_POST['$urlname']);
$dateofurll = isset($_POST['$dateofurl']);  

$createe = mysql_query ("CREATE TABLE 'urls' 
                        ( 'urlId' INT(4) NOT NULL PRIMARY KEY AUTO INCREMENT NOT NULL, 
                          'urlname' VARCHAR(50) NOT NULL,  
                          'dateofurl' DATETIME NOT NULL"
                       ); 

$insertt=mysql_query("INSERT INTO urls (urlId, urlname, dateofurl) 
                      VALUES ('$urlId', '$urlname', '$dateofurl')");
if(!$insertt){
   echo mysql_error();
} else 
   echo "a row has been created successfully";



$updatee = mysql_query("UPDATE urls SET(urlId, urlname, dateofurl) 
                        VALUES ('$urlId', '$urlname', '$dateofurl')");

if(!$updatee){
   echo mysql_error();
} else 
   echo "a row has been changed successfully";

$deletee = mysql_query("DELETE FROM urls 
                        SET(urlId, urlname, dateofurl) 
                        VALUES ('$urlId', '$urlname', '$dateofurl')");

Answer 1

这是mysql错误，而不是PHP，这意味着您正在尝试为PRIMARY KEY列添加重复值

我可以在你的代码中看到这一行

$createe = mysql_query ("CREATE TABLE IF NOT EXISTS 'urls' 
                        ( 'urlId' INT(4) NOT NULL PRIMARY KEY AUTO INCREMENT NOT NULL, 
                          'urlname' VARCHAR(50) NOT NULL,  
                          'dateofurl' DATETIME NOT NULL"
                       );

注意：使用CREATE TABLE IF NOT EXISTS因为您的脚本更有可能被执行多次，如果已经创建了TABLE，您的脚本不会产生任何错误

您的urlId是您的PRIMARY KEY并且是AUTO_INCREMENT，这意味着在插入数据时，您无需输入其值，插入新行时它会自动递增。

我的建议是从您的查询中移除urlid并将其设为这样，通过执行此操作，urlid的值将自动插入

$insertt=mysql_query("INSERT INTO urls ( urlname, dateofurl) 
                      VALUES ( '$urlname', '$dateofurl')");

Answer 2

你试过不指定你的urlID吗？它有一个自动增量..

查询shud就像这样

$insertt=mysql_query("INSERT INTO `urls` (`urlname`, `dateofurl`) VALUES ('$urlname', '$dateofurl')");

$updatee=mysql_query("UPDATE `urls` SET `urlname`='$urlname' , `dateofurl`='$dateofurl' WHERE `urlId`=$urlId");

$deletee= mysql_query("DELETE from `urls` WHERE `urlId`=$urlId");

php错误重复输入＆＃39; 0＆＃39;对于第1行的键1

2 个答案: