Question

select cast(datediff(minute,convert(time,'09:35 AM'),
       convert(time,'07:06 PM'))/60 as varchar)
       +':'+cast(datediff(minute,convert(time,'09:35 AM'),
       convert(time,'07:06 PM'))%60 as varchar)

输出：9:31

我是否还有其他功能可以缩短上述脚本。另外，我应该怎么做才能将输出变为09:31而不是9:31？

Answer 1

您可以使用样式114的CONVERT()来获取HH:mm

SELECT 
    CONVERT(nvarchar(5), 
        -- Get difference of time
        CONVERT(datetime,'07:06 PM') - CONVERT(datetime,'09:35 AM')
        , 114)

SQL Fiddle

修改

作为评论以避免日期时算术

SELECT CONVERT(varchar(5), DATEADD(minute, DATEDIFF(minute, convert(time,'09:35 AM'), convert(time,'07:06 PM')) , 0) , 114)

Answer 2

您可以在Sql Server中使用Format功能。

更新 - （示例）：这可能是您想要的：

select FORMAT(CONVERT(datetime,'9:31'),'HH:mm') AS 'time'

Answer 3

DECLARE @time1 AS VARCHAR(8) = '09:35 AM'
DECLARE @time2 AS VARCHAR(8) = '07:06 PM'

SELECT 
    time1   = CAST(@time1 AS TIME), 
    time2   = CAST(@time2 AS TIME),
    diff    = DATEDIFF(MINUTE, @time1, @time2),
    hh      = RIGHT('00' + CAST(DATEDIFF(MINUTE, CAST(@time1 AS TIME), CAST(@time2 AS TIME))/60 AS VARCHAR(2)), 2),
    mm      = RIGHT('00' + CAST(DATEDIFF(MINUTE, CAST(@time1 AS TIME), CAST(@time2 AS TIME))%60 AS VARCHAR(2)), 2),
    final   = RIGHT('00' + CAST(DATEDIFF(MINUTE, CAST(@time1 AS TIME), CAST(@time2 AS TIME))/60 AS VARCHAR(2)), 2) + ':' +
              RIGHT('00' + CAST(DATEDIFF(MINUTE, CAST(@time1 AS TIME), CAST(@time2 AS TIME))%60 AS VARCHAR(2)), 2)

在声明和/或转换为VARCHAR类型时，您应指定长度，否则SQL-Server将为您分配默认值。有时它是1，有时它是30。有关详细信息，请参阅此article。

另外，要将差异格式化为hh:mm，您需要使用适当的零数填充字符串。这是使用：

完成的

RIGHT('00' + str, 2)

Answer 4

只需尝试此广告检查是否符合您的要求：

SELECT FORMAT(GETDATE(),'hh:mm')

OR

SELECT (CONVERT(VARCHAR(5), GETDATE(), 114))

更好的选择，从两个给定的时间{h}：mm格式获得时间

4 个答案: