我想知道如何使用从查询中获取的数据创建表。
select COUNT (SIGPAREDEX) AS BloqueConcreto
from dbo.FICH_3_3$
where SIGPAREDEX ='BCO'
select COUNT (SIGPAREDEX) AS Ripios
from dbo.FICH_3_3$
where SIGPAREDEX ='RIP'
select COUNT (SIGPAREDEX) AS Minifalda
from dbo.FICH_3_3$
where SIGPAREDEX ='MIN'
select COUNT (SIGPAREDEX) As MaderaAcepillada
from dbo.FICH_3_3$
where SIGPAREDEX ='MAD'
select COUNT (SIGPAREDEX) AS LosetasConcreto from dbo.FICH_3_3$ where SIGPAREDEX = 'CPR'
Select COUNT (SIGPAREDEX) As MaderaRustica from dbo.FICH_3_3$ where SIGPAREDEX = 'MAR'
select COUNT (SIGPAREDEX) As LadrilloCuarteron from dbo.FICH_3_3$ where SIGPAREDEX = 'LAC'
select COUNT (SIGPAREDEX) AS LaminasMetalicas from dbo.FICH_3_3$ where SIGPAREDEX = 'MET'
select COUNT (SIGPAREDEX) As Plywood from dbo.FICH_3_3$ where SIGPAREDEX = 'PLY'
select COUNT (SIGPAREDEX) As BloqueDeBarro from dbo.FICH_3_3$ where SIGPAREDEX = 'BBA'
Select COUNT (SIGPAREDEX) As Katrinite from dbo.FICH_3_3$ where SIGPAREDEX = 'KAD'
Select COUNT (SIGPAREDEX) As LaminaFibroCemento from dbo.FICH_3_3$ where SIGPAREDEX = 'LFC'
Select COUNT (SIGPAREDEX) As ConcretoMonolitico from dbo.FICH_3_3$ where SIGPAREDEX = 'CMO'
Select COUNT (SIGPAREDEX) As PiedraCantera from dbo.FICH_3_3$ where SIGPAREDEX = 'PCA'
Select COUNT (SIGPAREDEX) As Adobe from dbo.FICH_3_3$ where SIGPAREDEX = 'ADO'
Select COUNT (SIGPAREDEX) As Convitec from dbo.FICH_3_3$ where SIGPAREDEX = 'COV'
Select COUNT (SIGPAREDEX) As Gypsum from dbo.FICH_3_3$ where SIGPAREDEX = 'GYP'
Select COUNT (SIGPAREDEX) As PanelFerroCemento from dbo.FICH_3_3$ where SIGPAREDEX = 'PFC'
Select COUNT (SIGPAREDEX) As PiedraBolon from dbo.FICH_3_3$ where SIGPAREDEX = 'PRC'
Select COUNT (SIGPAREDEX) As SinInformacion from dbo.FICH_3_3$ where SIGPAREDEX = 'SIN'
Select COUNT (SIGPAREDEX) As LaminasTroqueladas from dbo.FICH_3_3$ where SIGPAREDEX = 'LTR'
我尝试使用以下视图:
SELECT SIGPAREDEX ,
CASE
WHEN EXISTS (SELECT * FROM View1 ) THEN '1'
END AS [LTR],
CASE
WHEN EXISTS (SELECT * FROM View2 ) THEN '1'
END AS [SIN]
From dbo.FICH_3_3$
但这不是我想要的,我需要得到这样的东西:
Bloque concreto 11698
Ripios 29..
Minifalda 3109
Plywood a value
一张桌子里的所有东西
请尽快帮助我
此致
答案 0 :(得分:1)
以下是伪代码的答案。 您需要使用Union all作为子查询的名称。 这些名称必须相同,因为您正在构建一个表。
select 'YourDataTile' as Title,(select count(YOURCOL) as Value from YOURTABLE ) Value
union all
select 'YourOtherDataTile' as Title,(select count(YOUROTHERCOL) as Vvalue from YOUROTHERTABLETABLE ) Value
这是你的例子的开头
SELECT 'BloqueConcreto' as Title, (select COUNT (SIGPAREDEX) AS BloqueConcreto from dbo.FICH_3_3$ where SIGPAREDEX ='BCO') Value
union all
SELECT 'Ripios ' as Title, (select COUNT (SIGPAREDEX) AS Ripios from dbo.FICH_3_3$ where SIGPAREDEX ='RIP') Value
只需添加
union all select ....
用于所有查询