可以使用dup$Number
中的一列数值和DG中与dup$number
匹配的子列,并将其作为新数据框返回?
dup
Number Letter
59 Q
91 Q
19 Q
17 Q
DG
chr pos id ref alt refc altc qual cov line_21 line_26 line_28 line_31 line_32 line_38 line_40 line_41 line_42 line_45 line_48 line_49 line_57 line_59 line_69 line_73 line_75 line_83
1 2R 7006506 2R_7006506_SNP C A 169 26 999 29 0 0 0 2 0 0 0 0 0 0 0 0 0 0 0 0 2 -
答案 0 :(得分:0)
尝试
indx <- grep('line', names(DG))
DG[indx[as.numeric(sub('.*_', '', names(DG)[indx])) %in% dup$Number]]
# line_59
#1 0