我正在学习如何使用Eclipse的Maven插件来使用Sphinx4。
我在GitHub上找到了转录演示并对其进行了修改以处理我自己的文件。音频文件是16位,单声道,16khz。大约13秒。我注意到它听起来像是慢动作。
文件中的文字是,“还要确保您可以轻松访问录制文件,以便在收到问题时上传文件”。
我正在尝试转录该文件,我的结果非常糟糕。我试图找到彻底解释如何改进结果的论坛帖子或链接,或者我没有正确做的事情让我无处可去。
我希望加强转录的准确性,但是由于我当前项目必须处理的数据类型的差异,我希望避免自己培训模型。这是不可能的,是我正在使用的代码吗?
代码
(注意:音频文件位于https://instaud.io/8qv)
public class App {
public static void main(String[] args) throws Exception {
System.out.println("Loading models...");
Configuration configuration = new Configuration();
// Load model from the jar
configuration
.setAcousticModelPath("resource:/edu/cmu/sphinx/models/en-us/en-us");
// You can also load model from folder
// configuration.setAcousticModelPath("file:en-us");
configuration
.setDictionaryPath("resource:/edu/cmu/sphinx/models/en-us/cmudict-en-us.dict");
configuration
.setLanguageModelPath("resource:/edu/cmu/sphinx/models/en-us/en-us.lm.dmp");
StreamSpeechRecognizer recognizer = new StreamSpeechRecognizer(
configuration);
FileInputStream stream = new FileInputStream(new File("/home/tmscanlan/workspace/example/vocaroo_test_revised.wav"));
// stream.skip(44); I commented this out due to the short length of my file
// Simple recognition with generic model
recognizer.startRecognition(stream);
SpeechResult result;
while ((result = recognizer.getResult()) != null) {
// I added the following print statements to get more information
System.out.println("\ngetWords() before loop: " + result.getWords());
System.out.format("Hypothesis: %s\n", result.getHypothesis());
System.out.print("\nThe getResult(): " + result.getResult()
+ "\nThe getLattice(): " + result.getLattice());
System.out.println("List of recognized words and their times:");
for (WordResult r : result.getWords()) {
System.out.println(r);
}
System.out.println("Best 3 hypothesis:");
for (String s : result.getNbest(3))
System.out.println(s);
}
recognizer.stopRecognition();
// Live adaptation to speaker with speaker profiles
stream = new FileInputStream(new File("/home/tmscanlan/workspace/example/warren_test_smaller.wav"));
// stream.skip(44); I commented this out due to the short length of my file
// Stats class is used to collect speaker-specific data
Stats stats = recognizer.createStats(1);
recognizer.startRecognition(stream);
while ((result = recognizer.getResult()) != null) {
stats.collect(result);
}
recognizer.stopRecognition();
// Transform represents the speech profile
Transform transform = stats.createTransform();
recognizer.setTransform(transform);
// Decode again with updated transform
stream = new FileInputStream(new File("/home/tmscanlan/workspace/example/warren_test_smaller.wav"));
// stream.skip(44); I commented this out due to the short length of my file
recognizer.startRecognition(stream);
while ((result = recognizer.getResult()) != null) {
System.out.format("Hypothesis: %s\n", result.getHypothesis());
}
recognizer.stopRecognition();
System.out.println("...Printing is done..");
}
}
这是输出(我拍摄的相册):http://imgur.com/a/Ou9oH
答案 0 :(得分:1)
正如Nikolay所说,音频听起来很奇怪,可能是因为你没有以正确的方式重新采样。 要将音频从原始22050 Hz下采样到所需的16kHz,您可以运行以下命令:
sox Vocaroo.wav -r 16000 Vocaroo16.wav
Vocaroo16.wav听起来会好得多,它会(可能)给你更好的ASR结果。