Question

出于某种原因，这给了我一个错误。 swearWordPair被定义为[String]。例如 ["Hello", "Hi"]

let swearWordsAndReplacements : [[String]] = [["anus", "butt"], ["arse", "butt"]]

这给我的错误是

Cannot invoke 'stringByReplacingOccurrencesOfString' with an argument list of type '(String, withString: String, options: NSStringCompareOptions, range: NSRange)

然而，我查找了这个函数的参数，似乎我的所有参数都是正确的。这是一个快速的错误吗？

var string = insult
for swearWordPair in swearWordsAndReplacements {
    string = string.stringByReplacingOccurrencesOfString(swearWordPair[0],
        withString: swearWordPair[1],
        options: NSStringCompareOptions.CaseInsensitiveSearch,
        range: NSMakeRange(0, count(string)))
}

Answer 1

Range不是NSRange，而是Swift范围。在这种情况下，您可以传递nil来代表整个String：

string = string.stringByReplacingOccurrencesOfString(swearWordPair[0],
    withString: swearWordPair[1],
    options: .CaseInsensitiveSearch,
    range: nil)

如果您想限制范围，可以像这样创建Range<String.Index>：

var string = "I laid my head at the head of the bed"

// Only replace within the first 15 characters
let myrange = string.startIndex ..< advance(string.startIndex, 15)

string = string.stringByReplacingOccurrencesOfString("head",
    withString: "blanket",
    options: .CaseInsensitiveSearch,
    range: myrange)

println(string)

输出：

我把毯子放在床头

stringByReplacingOccurrencesOfString给出奇怪的错误

1 个答案: