Python:ipaddress.AddressValueError:预计至少有3个部分

时间:2015-06-23 07:04:48

标签: python string unicode ip-address

ipaddress.IPv4Network的属性可用于检查是否保留了任何IP地址。

在IPython中:

In [52]: IPv4Address(u'169.254.255.1').is_private
Out[52]: False

然而,如果我在函数中尝试完全相同的东西:

import ipaddress
def isPrivateIp(ip):
    unicoded = unicode(ip)
    if ipaddress.IPv4Network(unicoded).is_private or ipaddress.IPv6Network(unicoded).is_private:
        return True
    else:
        return False

print isPrivateIp(r'169.254.255.1')

我明白了:

  File "isPrivateIP.py", line 13, in <module>
    print isPrivateIp(ur'169.254.255.1')
  File "isPrivateIP.py", line 7, in isPrivateIp
    if ipaddress.IPv4Network(unicoded).is_private or ipaddress.IPv6Network(unicoded).is_private:
  File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/ipaddress.py", line 2119, in __init__
    self.network_address = IPv6Address(self._ip_int_from_string(addr[0]))
  File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/ipaddress.py", line 1584, in _ip_int_from_string
    raise AddressValueError(msg)
ipaddress.AddressValueError: At least 3 parts expected in u'169.254.255.1'

为什么会这样?

注意:在python 2中,必须将ip地址作为unicode对象传递给ipaddress函数,因此在字符串输入unicode()上调用ip

1 个答案:

答案 0 :(得分:1)

ipaddress.IPv6Network()的预期输入与ipaddress.IPv4Network()不同。如果您从代码中删除or ipaddress.IPv6Network(unicoded).is_private,则可以正常使用。您可以从here了解更多信息。