“Stream不可读”使用ReadAsStreamAsync与StreamReader

时间:2015-06-23 00:27:45

标签: c# stream async-await task-parallel-library streamreader

我有以下代码来使用StreamReader读取和处理Http get请求的响应:

try
{
    Stream stream = await ExecuteRequestAsync(uriBuilder.Uri, HttpMethod.Get).ConfigureAwait(false);
    if (stream != null)
    {
        using (StreamReader sr = new StreamReader(stream))
        {
            using (JsonTextReader reader = new JsonTextReader(sr))
            {
                ...
            }
        }
    }
}
catch (Exception ReadingStreamException)
{

}

private async Task<stream> ExecuteRequestAsync(Uri uri, HttpMethod method)
{
    Stream stream;
    using (HttpRequestMessage httpRequestMessage = new HttpRequestMessage(method, uri))
    {
    try
    {
        stopwatch.Start();
        using (HttpResponseMessage responseMessage = await this.httpClient.SendAsync(httpRequestMessage).ConfigureAwait(false))
        {
            stream = await responseMessage.Content.ReadAsStreamAsync().ConfigureAwait(false);
        }
    }
    catch(Exception GettingStreamException)
    {
        // Error checking code
    }

    return stream;
}

使用(StreamReader sr = new StreamReader(stream))的行向ArgumentException类型的ReadingStreamException抛出异常,其详细信息为“Stream is not readable”。上面的代码有问题吗?

1 个答案:

答案 0 :(得分:8)

这是因为当您处置HttpResponseMessage时,它会处置基础流。来自the source

private HttpContent content;
protected virtual void Dispose(bool disposing)
{
    if (disposing && !disposed)
    {
        disposed = true;
        if (content != null)
        {
            content.Dispose();
        }
    }
}

您可以复制流,也可以不处理HttpResponseMessage,因为在将基础流传递给StreamReader时,无论如何都要处置它。我会选择后者:

private async Task<Stream> ExecuteRequestAsync(Uri uri, HttpMethod method)
{
    Stream stream = null;
    using (HttpRequestMessage httpRequestMessage = new HttpRequestMessage(method, uri))
    {
       try
       {
          stopwatch.Start();
          HttpResponseMessage responseMessage = await httpClient
                                                      .SendAsync(httpRequestMessage)
                                                      .ConfigureAwait(false);

          stream = await responseMessage.Content.ReadAsStreamAsync()
                                                .ConfigureAwait(false);
       }
       catch(Exception GettingStreamException)
       {
          // Error checking code
       }  
    }
    return stream;
}