Question

我想弄清楚哪个看起来非常简单，但我无法找到一种方法来做同样的事情。

考虑以下表和数据，

create table dummy_query 
(id varchar2(20), amount number(10,2), memo varchar(20));

insert into dummy_query values('1', 10.00, 'Memo');

insert into dummy_query values('1', 20.00, 'Memo1');

我希望将值设为：

Id MemoValue  Memo1Value TotalSum

----------

1   10.00       20.00       30.00

有没有办法以这种方式获取数据？

谢谢！

Answer 1

SQL Fiddle

Oracle 11g R2架构设置：

create table dummy_query (id, amount, memo) AS
           SELECT '1', 10.00, 'Memo'  FROM DUAL
UNION ALL  SELECT '1', 20.00, 'Memo1' FROM DUAL
UNION ALL  SELECT '1', 30.00, 'Memo2' FROM DUAL;

查询1 ：

如果TotalSum是所有备忘金额的总和（而不只是Memo和Memo1），那么您可以这样做：

SELECT ID,
       SUM( CASE memo WHEN 'Memo'  THEN amount END ) AS MemoValue,
       SUM( CASE memo WHEN 'Memo1' THEN amount END ) AS Memo1Value,
       SUM( amount ) AS TotalSum
FROM   dummy_query
GROUP BY id

<强> Results ：

| ID | MEMOVALUE | MEMO1VALUE | TOTALSUM |
|----|-----------|------------|----------|
|  1 |        10 |         20 |       60 |

查询2 ：

但是如果TotalSum只是MemoValue + Memo1Value，那么添加一个where子句：

SELECT ID,
       SUM( CASE memo WHEN 'Memo'  THEN amount END ) AS MemoValue,
       SUM( CASE memo WHEN 'Memo1' THEN amount END ) AS Memo1Value,
       SUM( amount ) AS TotalSum
FROM   dummy_query
WHERE  memo IN ( 'Memo', 'Memo1' )
GROUP BY id

<强> Results ：

| ID | MEMOVALUE | MEMO1VALUE | TOTALSUM |
|----|-----------|------------|----------|
|  1 |        10 |         20 |       30 |

查询3 ：

或者，如果您因其他原因需要包含所有行，那么您可以这样做：

SELECT ID,
       SUM( CASE memo WHEN 'Memo'  THEN amount END ) AS MemoValue,
       SUM( CASE memo WHEN 'Memo1' THEN amount END ) AS Memo1Value,
       SUM( CASE WHEN memo IN ( 'Memo', 'Memo1' ) THEN amount END ) AS TotalSum
FROM   dummy_query
GROUP BY id

<强> Results ：

| ID | MEMOVALUE | MEMO1VALUE | TOTALSUM |
|----|-----------|------------|----------|
|  1 |        10 |         20 |       30 |

Answer 2

我对PIVOT不是很熟悉，但你尝试了我确实在那里建立了查询。希望这是你需要的 -

SELECT a.*, b.SUM_AMT
  FROM ((SELECT ID, amount, memo FROM dummy_query) PIVOT (SUM (amount)
                                                   FOR (memo)
                                                   IN ('Memo', 'Memo1'))) a,
       (  SELECT ID, SUM (AMOUNT) "SUM_AMT"
            FROM dummy_query
        GROUP BY id) b
 WHERE a.id = b.id

可以有更好的方法来重新开始，让我们看看其他人必须分享的内容。

Answer 3

已启动pivot的解决方案：

select id, memo, memo1, memo+memo1 msum from ( 
    select * from dummy_query 
    pivot (sum(amount) for (memo) in ('Memo' memo,'Memo1' memo1)))

更传统，没有支点：

select id, memo, memo1, memo1+memo msum from (
  select id, 
    sum(case when memo='Memo' then amount end) memo, 
    sum(case when memo='Memo1' then amount end) memo1
  from dummy_query group by id)

^SQLFiddle

如何在同一列上聚合？

3 个答案: