Question

我面临的情况就是这样：

我从数据库中读取数据并将其转储到网页的表格中。然后，根据列的值，显示或不显示下拉列表。并将下拉列表中的值写回数据库。

我使用...提交，但$ _GET没有关于下拉列表的值。

我列出了这里设置的整个代码。

非常感谢任何帮助！

$GCdataSQL = "select * from table_name";
$GCdata = new Query($GCdataSQL);

$table = "<form method='GET'><table class='datatable table table-condensed ' id='query-data'><thead><tr>";
$ColName = array('col1','col2','col3','col4', 'col5', 'col6', 'col7', 'col8');
foreach ($ColName as $Name){
    $table .= "<th>$Name</th>";
}
$table .= "</tr></thead><tbody>";
while ($GCdataRow = $GCdata->fetchRow()){
        $emplid = $GCdataRow['emplid'];
        $term = $GCdataRow['term'];
        $handled = $GCdataRow['handled'];
    if ($GCdataRow['code'] == 'UNKNOW' || $GCdataRow['code'] == 'Not Repeated'){$GCdataRow['code']= '';}

    if ($GCdataRow['local_action'] !== $GCdataRow['new_action']){
        $table .=  "<tr bgcolor= 'LightPink'>"; 

    }
    else {
        $table .=  "<tr>";
    }

    foreach($GCdataRow as $key=>$value){

        if ($key == 'emplid'){
            $table .="<td><a href='link' target = '_blank'>$value</a></td>";
        }
        else if ($key == 'new_action'){
            $table .="<td><a href='link' target = '_blank'>$value</a></td>";
        }
        else if ($key == 'handled' && $handled == 'Not Reviewed'){

            $table .="<td><select name = 'handlecode'><option value = 'Not Reviewed'>Not Reviewed</option><option value = 'Handled by Script'>Handled by Script</option><option value = 'Handled Manually'>Handled Manually</option><option value = 'Leave It'>Leave It</option></select></td>";

        }
        else {
            $table .=  "<td>".htmlentities($value)."</td>"; 
            }

        }

        $table .=  "</tr>";
        $loopcount++;
    }

    if(isset($table)) {$table .=  "</tbody></table>";}
   echo $table;
   echo "<button type='submit' class = 'btn btn-primary' style = 'position: absolute; left:50%;' >Submit</button></form>";

Answer 1

最后我将表单方法更改为POST，一切都很好！现在值在$ _POST中，我可以使用它们插入数据库！

谢谢！

如何从表的下拉列表中将值传递给$ _GET

1 个答案: