Question

非常感谢那些回复的人。 SQL Server中是否有一种方法可以从table1获取数据并输出像table2这样的数据？

谢谢！

表1：

+---------+-----------+----------+------------------+
|  Name   |    DOB    | Agent ID |    Agent Name    |
+---------+-----------+----------+------------------+
| subject | 4/20/1960 | 4444     | Smith            |  
+---------+-----------+----------+------------------+
| subject | 4/20/1960 | 4444     | John             |
+---------+-----------+----------+------------------+
| subject | 4/20/1960 | 4444     | Larry            |
+---------+-----------+----------+------------------+

表2：

+---------+-----------+----------+------------------+
|  Name   |    DOB    | Agent ID |    Agent Name    |
+---------+-----------+----------+------------------+
| subject | 4/20/1960 | 4444     | Smith,John,Larry |
+---------+-----------+----------+------------------+

Answer 1

对于SQL Server 2005+，请使用STUFF＆amp; FOR XML PATH创建逗号分隔列表：

SELECT DISTINCT
       t.name,
       t.dob,
       t.agentid,
       STUFF(ISNULL(SELECT ', ' + x.agentname
                      FROM TABLE1 x
                     WHERE x.agentid = t.agentid
                  GROUP BY x.agentname
                   FOR XML PATH ('')), ''), 1, 2, '')
  FROM TABLE1 t

Answer 2

SELECT DISTINCT t.Name, t.DOB, t.AgentID, x.AgentName 
FROM Table1 t
CROSS APPLY (SELECT CASE WHEN ROW_NUMBER() OVER (ORDER BY AgentName) = 1 
                         THEN '' ELSE ', ' END + AgentName 
             FROM Table1
             WHERE AgentID = t.AgentID
             AND AgentName IS NOT NULL
             FOR XML PATH(''))x(AgentName)

更正SQL语法？

2 个答案: