Question

如何删除＆＃34;表＆＃34;从HTML使用python？

我有这样的情况：

paragraph = '''
<p>Lorem ipsum dolor sit amet, consectetur adipisicing elit. Quidem molestiae consequuntur officiis corporis sint.<br /><br />
<table>
<tr>
<td>
    text title
</td>
<td>
    text title 2
</td>
</tr>
</table>
<p> lorem ipsum</p>
'''

如何使用python删除上面的表结构内容？我希望产生的输出如下：

paragraph = '''
<p>Lorem ipsum dolor sit amet, consectetur adipisicing elit. Quidem molestiae consequuntur officiis corporis sint.<br /><br />
<p> lorem ipsum</p>
'''

Answer 1

您可以使用BeautifulSoup，尤其是PageElement.extract()

In [16]: from bs4 import BeautifulSoup

In [17]: soup = BeautifulSoup("""<p>Lorem ipsum dolor sit amet, consectetur adipisicing elit. Quidem molestiae consequuntur officiis corporis sint.<br /><br />
   ....: <table>
   ....: <tr>
   ....: <td>
   ....:     text title or some
   ....: </td>
   ....: </tr>
   ....: </table>
   ....: <p> lorem ipsum</p>""")

In [18]: _ = soup.table.extract()

In [19]: soup
Out[19]: 
<html><body><p>Lorem ipsum dolor sit amet, consectetur adipisicing elit. Quidem molestiae consequuntur officiis corporis sint.<br/><br/>
</p>
<p> lorem ipsum</p></body></html>

Answer 2

您也可以尝试这种基本的字符串格式

paragraph = paragraph[:paragraph.find('<table>')] +     # Find the starting letter of '<table>'
            paragraph[paragraph.find('</table>')+       # Find the starting letter of </table>
            (len('<\table>')+1):]                       # Add 1 because length starts from zero

print(paragraph)

即使是基本文本提取的工作

Answer 3

使用正则表达式很复杂，这是我提出的一种愚蠢方式：

def remove_table(s):
    left_index = s.find('<table>')
    if -1 == left_index:
        return s
    right_index = s.find('</table>', left_index)
    return s[:left_index] + remove_table(s[right_index + 8:])

结果中可能有一些空白行。

如何从这种情况下删除python结构？

3 个答案: