Question

我有一个包含成员函数的类，我希望将其传递给std::thread的构造函数。

#include <thread>
#include <iostream>

struct StatsClientImpl
{
    std::thread t;
    size_t q_len;

    StatsClientImpl() : q_len(0)
    {
        t = std::thread(&StatsClientImpl::de_q, this);
    }

    ~StatsClientImpl()
    {
        if (t.joinable())
            t.join();
    }

    void de_q()
    {
        std::cout << "in de_q\n";
    }
};

int main()
{
    StatsClientImpl s;
}

我收到以下错误：

/Users/apple/platform/stats-client/src/main/cpp/StatsClientImpl.cpp:21:17: error: no matching constructor for initialization of 'std::thread'
    std::thread te(&StatsClientImpl::de_q, this);
                ^  ~~~~~~~~~~~~~~~~~~~~~~~~~~~~
/Applications/Xcode.app/Contents/Developer/Toolchains/XcodeDefault.xctoolchain/usr/bin/../include/c++/v1/thread:374:9: note: candidate constructor template not viable: requires single argument '__f', but 2 arguments were provided
thread::thread(_Fp __f)
        ^
/Applications/Xcode.app/Contents/Developer/Toolchains/XcodeDefault.xctoolchain/usr/bin/../include/c++/v1/thread:263:5: note: candidate constructor not viable: requires 1 argument, but 2 were provided
    thread(const thread&);
    ^
/Applications/Xcode.app/Contents/Developer/Toolchains/XcodeDefault.xctoolchain/usr/bin/../include/c++/v1/thread:270:5: note: candidate constructor not viable: requires 0 arguments, but 2 were provided
    thread() _NOEXCEPT : __t_(0) {}

Answer 1

C ++ 11线程允许直接调用非静态方法。您使用的语法仅用于此，只需将de_q_caller替换为de_q：

t = std::thread(&StatsClientImpl::de_q, this);

更新：因为您的编译器似乎不允许这样做，请尝试

t = std::thread(std::bind(&StatsClientImpl::de_q, this));

clang编译器可能需要添加以下编译器选项：

-std=c++11

使用类构造函数在线程中启动成员函数

1 个答案: