Question

我希望用户只在UITextField中输入数值。在iPhone上我们可以显示数字键盘，但在iPad上，用户可以切换到任何键盘。

有没有办法限制用户只输入UITextField中的数值？

Answer 1

这是我的2分。 （仅在Swift 2上测试）

func textField(textField: UITextField, shouldChangeCharactersInRange range: NSRange, replacementString string: String) -> Bool {

  let aSet = NSCharacterSet(charactersInString:"0123456789").invertedSet
  let compSepByCharInSet = string.componentsSeparatedByCharactersInSet(aSet)
  let numberFiltered = compSepByCharInSet.joinWithSeparator("")
  return string == numberFiltered

}

这只是一点点严格。没有小数点。

希望有所帮助:)

PS：无论如何，我认为你照顾了代表。

更新：Swift 3.0 ：

func textField(_ textField: UITextField, shouldChangeCharactersIn range: NSRange, replacementString string: String) -> Bool {

    let aSet = NSCharacterSet(charactersIn:"0123456789").inverted
    let compSepByCharInSet = string.components(separatedBy: aSet)
    let numberFiltered = compSepByCharInSet.joined(separator: "")
    return string == numberFiltered
}

Answer 2

swift 3.0及以上版本的解决方案

func textField(_ textField: UITextField, shouldChangeCharactersIn range: NSRange, replacementString string: String) -> Bool
  {
    let allowedCharacters = CharacterSet.decimalDigits
    let characterSet = CharacterSet(charactersIn: string)
    return allowedCharacters.isSuperset(of: characterSet)
  }

Answer 3

在Swift 4.1和Xcode 9.4.1中

将 UITextFieldDelegate 添加到您的班级

class YourViewController: UIViewController, UITextFieldDelegate

然后将此代码写入您的 viewDidLoad（）

mobileNoTF.delegate = self

编写此文本字段委托函数

//MARK - UITextField Delegates
func textField(_ textField: UITextField, shouldChangeCharactersIn range: NSRange, replacementString string: String) -> Bool {
    //For mobile numer validation
    if textField == mobileNoTF {
        let allowedCharacters = CharacterSet(charactersIn:"+0123456789 ")//Here change this characters based on your requirement
        let characterSet = CharacterSet(charactersIn: string)
        return allowedCharacters.isSuperset(of: characterSet)
    }
    return true
}

Answer 4

Swift 2.0

仅允许数字和一个＆＃34;。＆＃34; uitextfield中的小数。

func textField(textField: UITextField,shouldChangeCharactersInRange range: NSRange,replacementString string: String) -> Bool
{
    let newCharacters = NSCharacterSet(charactersInString: string)
    let boolIsNumber = NSCharacterSet.decimalDigitCharacterSet().isSupersetOfSet(newCharacters)
    if boolIsNumber == true {
        return true
    } else {
        if string == "." {
            let countdots = textField.text!.componentsSeparatedByString(".").count - 1
            if countdots == 0 {
                return true
            } else {
                if countdots > 0 && string == "." {
                    return false
                } else {
                    return true
                }
            }
        } else {
            return false
        }
    }
}

Answer 5

在Swift 3

中使用单个（。）点接受文本字段中的十进制值

func textField(_ textField: UITextField, shouldChangeCharactersIn range: NSRange, replacementString string: String) -> Bool {
    let inverseSet = NSCharacterSet(charactersIn:"0123456789").inverted

    let components = string.components(separatedBy: inverseSet)

    let filtered = components.joined(separator: "")

    if filtered == string {
        return true
    } else {
        if string == "." {
            let countdots = textField.text!.components(separatedBy:".").count - 1
            if countdots == 0 {
                return true
            }else{
                if countdots > 0 && string == "." {
                    return false
                } else {
                    return true
                }
            }
        }else{
            return false
        }
    }
}

Answer 6

func textField(textField: UITextField, shouldChangeCharactersInRange range: NSRange, replacementString string: String) -> Bool {
    // return true if the replacementString only contains numeric characters
    let digits = NSCharacterSet.decimalDigitCharacterSet()
    for c in string {
        if !digits.characterIsMember(c) {
            return false
        }
    }

    return true
}

即使用户切换键盘或尝试将非数字字符串粘贴到文本字段中，此解决方案仍然有效。

确保设置相应文本字段的delegate属性。

Answer 7

仅支持iPhone的解决方案

在您从中获取这些值的任何UITextField中，您可以指定当某人触摸文本字段时您想要显示的键盘类型。

E.G。一个纯数字键盘。

喜欢这个截图：

<强> ipad公司

iPad不支持数字键盘，因此您可以选择不支持iPad，验证提交后的字段，也可以按照此处的其他建议在iPad上运行时创建理智的行为。

Answer 8

//代替这些，您只需将键盘更改为数字类型

yourtextfield.keyboardType = UIKeyboardType.numberPad

Answer 9

使用数字格式化程序

Swift 4.x

func textField(_ textField: UITextField, shouldChangeCharactersIn range: NSRange, replacementString string: String) -> Bool {
      let s = NSString(string: textField.text ?? "").replacingCharacters(in: range, with: string)
      guard !s.isEmpty else { return true }
      let numberFormatter = NumberFormatter()
      numberFormatter.numberStyle = .none
      return numberFormatter.number(from: s)?.intValue != nil
 }

Answer 10

这是一个简单的解决方案，您需要在控制器中将“编辑已更改”事件连接到此方法

Swift 4

@IBAction func valueChanged(_ sender: UITextField) {
    if let last = sender.text?.last {
        let zero: Character = "0"
        let num: Int = Int(UnicodeScalar(String(last))!.value - UnicodeScalar(String(zero))!.value)
        if (num < 0 || num > 9) {
            //remove the last character as it is invalid
            sender.text?.removeLast()
        }
    }
}

Answer 11

设置KeyboardType属性：-数字键盘 TextField委托，请在下面的代码中编写

  func textField(_ textField: UITextField, shouldChangeCharactersIn 
  range: NSRange, replacementString string: String) -> Bool {

    if textField.text?.count == 0 && string == "0" {
        return false
    }
    return string == string.filter("0123456789".contains)
}

数字不应从0开始，而输入数字+ ve。

Answer 12

在swift 3.0中测试

func textField(textField: UITextField, shouldChangeCharactersInRange range: NSRange, replacementString string: String) -> Bool

{         
    let numberOnly = NSCharacterSet.init(charactersIn: "0123456789")
    let stringFromTextField = NSCharacterSet.init(charactersIn: string)
    let strValid = numberOnly.isSuperset(of: stringFromTextField as CharacterSet)

     return strValid
 }

Answer 13

虽然大多数这些解决方案都有效，但请注意，在某些本地化中，小数位用＆＃34;，＆＃34;而不是＆＃34;。＆＃34;

更简洁的方法是

func textField(textField: UITextField, shouldChangeCharactersInRange range: NSRange, replacementString string: String) -> Bool {
    let decimalCharacter = NSNumberFormatter().decimalSeparator
    let characterSet = NSMutableCharacterSet.decimalDigitCharacterSet()
    characterSet.addCharactersInString(decimalCharacter)

    return replacementString.rangeOfCharacterFromSet(characterSet.invertedSet) == nil
}

Answer 14

func textField(textField: UITextField, shouldChangeCharactersInRange range: NSRange, replacementString string: String) -> Bool {
    if let numRange = string.rangeOfCharacterFromSet(NSCharacterSet.letterCharacterSet()) {
        return false
    } else {
        return true
    }
   }

Answer 15

要仅允许数字和一个十进制运算符，您可以使用此解决方案：

func textField(textField: UITextField, shouldChangeCharactersInRange range: NSRange, replacementString string: String) -> Bool {
    let isNumber = NSCharacterSet.decimalDigitCharacterSet().isSupersetOfSet(NSCharacterSet(charactersInString: string))

    return isNumber || (string == NSNumberFormatter().decimalSeparator && textField.text?.containsString(string) == false)
}

Answer 16

以下解决方案有两个好处：

这是一个单行代码
它限制输入，以使输入字段中的整体文本为有效数字。其他解决方案将数字限制为有效数字，但这导致用户能够输入“ 4 ... 5”

    func textField(_ textField: UITextField, shouldChangeCharactersIn range: NSRange, replacementString string: String) -> Bool {
        return NumberFormatter().numberFrom(text: (textField.text ?? "") + string) != nil
    }

Answer 17

像这样扩展你的视图控制器：

class MyViewController: UIViewController, UITextFieldDelegate

在viewDidLoad函数中扩展到您的文本字段，如下所示：

myTextField.delegate = self

然后使用以下功能：

func textField(_ textField: UITextField, shouldChangeCharactersIn range: NSRange, replacementString string: String) -> Bool {
    let isNumber = CharacterSet.decimalDigits.isSuperset(of: CharacterSet(charactersIn: string))
    let withDecimal = (
        string == NumberFormatter().decimalSeparator &&
        textField.text?.contains(string) == false
    )
    return isNumber || withDecimal
}

现在确保用户只能输入十进制数字。

斯威夫特4 + 仅接受数字并接受一个分隔符

Answer 18

首先，您必须自己继承UITextFieldDelegate类课

class ViewController: UIViewController, UITextFieldDelegate {

第二次添加IBOutlet

@IBOutlet weak var firstName: UITextField!

第三个必须确保该对象正在使用

override func viewDidLoad() {
        super.viewDidLoad()
   firstName.delegate = self
}


func textField(_ textField: UITextField, shouldChangeCharactersIn range: NSRange, replacementString string: String) -> Bool {
    if textField == firstName {
                let allowedCharacters = "1234567890"
                let allowedCharacterSet = CharacterSet(charactersIn: allowedCharacters)
                let typedCharacterSet = CharacterSet(charactersIn: string)
                let alphabet = allowedCharacterSet.isSuperset(of: typedCharacterSet)
                return alphabet


      }
  }

Answer 19

在完成Big Nerd Ranch书时我实际上已经完成了这个，我的解决方案是：

func textField(textField: UITextField, 
    shouldChangeCharactersInRange range: NSRange, 
    replacementString string: String) -> Bool {

    let newCharacters = NSCharacterSet(charactersInString: string)
    return NSCharacterSet.decimalDigitCharacterSet().isSupersetOfSet(newCharacters)
}

这只允许数字0-9，以允许“。”同样更复杂，因为你只能允许一个“。”

Answer 20

允许一些特征

func CheckAddress(string:String) -> Bool  {
        let numberOnly = NSCharacterSet.init(charactersIn: "0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz-@,&#/")
        let stringFromTextField = NSCharacterSet.init(charactersIn: string)
        return numberOnly.isSuperset(of: stringFromTextField as CharacterSet)
    }

print("\(CheckAddress(string: "123"))") //True
print("\(CheckAddress(string: "asdf-"))") //True
print("\(CheckAddress(string: "asd123$"))") //false

Answer 21

我编辑了Raj Joshi的版本以允许一个点或一个逗号：

func textField(_ textField: UITextField, shouldChangeCharactersIn range: NSRange, replacementString string: String) -> Bool {

    let inverseSet = CharacterSet(charactersIn:"0123456789").inverted
    let components = string.components(separatedBy: inverseSet)
    let filtered = components.joined(separator: "")

    if filtered == string {
        return true
    } else {
        if string == "." || string == "," {
            let countDots = textField.text!.components(separatedBy:".").count - 1
            let countCommas = textField.text!.components(separatedBy:",").count - 1

            if countDots == 0 && countCommas == 0 {
                return true
            } else {
                return false
            }
        } else  {
            return false
        }
    }
}

Answer 22

func textField(_ textField: UITextField, shouldChangeCharactersIn range: NSRange, replacementString string: String) -> Bool

        {
            let textString = (textField.text! as NSString).replacingCharacters(in: range, with: string)

            if textField == self.phoneTextField  && string.characters.count > 0{
                let numberOnly = NSCharacterSet.decimalDigits
                let strValid = numberOnly.contains(UnicodeScalar.init(string)!)
                return strValid && textString.characters.count <= 10
            }
            return true
        }

上面代码中的

在swift 3中工作 NSCharacterSet。的 decimalDigits
你也只用字母
NSCharacterSet。的字母
和大写，小写字母，字母数字，空格 使用相同的代码或See the Link

Answer 23

我认为您可以通过实现UITextInputTraits协议强制更改键盘类型，可选var keyboardType

//class ViewController: UIViewController, UITextInputTraits {

@IBOutlet weak var textFieldKeyboardType: UITextField!{
    didSet{
        textFieldKeyboardType.keyboardType = UIKeyboardType.NumberPad
    }
}
var keyboardType: UIKeyboardType { 
    get{ 
        return textFieldKeyboardType.keyboardType
    } 
    set{ 
        if newValue != UIKeyboardType.NumberPad{
            self.keyboardType = UIKeyboardType.NumberPad
        }
    } 
}

Answer 24

这是一个更清洁的解决方案：

 guard CharacterSet(charactersIn: "123456789").isSuperset(of: CharacterSet(charactersIn: string)) else {
     return false
 }
 return true

对于小数，只需添加.，例如123456789.

Answer 25

以下是我在Swift 3.0中使用的代码，该代码改编自Mr H的代码。差异是因为：

a）Swift 3.0中的委托函数声明已更改。 New declaration here

b）NSCharacterSet声明已更改。

func textField(_ shouldChangeCharactersIntextField: UITextField, shouldChangeCharactersIn range: NSRange, replacementString string: String) -> Bool
{

        let inverseSet = NSCharacterSet(charactersIn:"0123456789").inverted

        let components = string.components(separatedBy: inverseSet)

        let filtered = components.joined(separator: "")

        return string == filtered

}

Answer 26

好像没有足够的答案，这就是我的。我认为允许小数分隔符的每个例子在本地化，退格或复制/粘贴方面都存在缺陷。

func textField(textField: UITextField, shouldChangeCharactersInRange range: NSRange, replacementString string: String) -> Bool {
    if string.isEmpty {return true} //allow for backspace

    let decimalSeparator = NSNumberFormatter().decimalSeparator ?? "."
    let validChars = NSMutableCharacterSet(charactersInString: decimalSeparator)
    validChars.formUnionWithCharacterSet(NSCharacterSet.decimalDigitCharacterSet())

    if validChars.isSupersetOfSet(NSCharacterSet(charactersInString: string)){
        switch string.componentsSeparatedByString(decimalSeparator).count-1 {
        case 0: //no decimals
            return true

        case 1: //if adding decimal, only allow if no existing decimal
            if let existingText = textField.text{
                return existingText.componentsSeparatedByString(decimalSeparator).count <= 1
            }
            else {return true}

        default: //invalid decimals
            return false
        }
    }

    return false
}

Answer 27

同时解决小数和整数的方法：

 func textField(_ textField: UITextField, shouldChangeCharactersIn range: NSRange, replacementString string: String) -> Bool {
    let currentText = textField.text
    let futureString = currentText.substring(toIndex: range.location) + string + currentText.substring(fromIndex: range.location + range.length)
    
    if futureString.count == 0 {
        return true
    }
    
    if isDecimal {
        if let numberAsDouble = Double(futureString), numberAsDouble.asPrice.count >= futureString.count {
            return true
        }
    } else if let numberAsInt = Int(futureString), "\(numberAsInt)".count == futureString.count {
        return true
    }
    
    return false
}

Answer 28

Double代表的UITextFieldDelegate数字的死简单解决方案（请注意，这不是最好的用户友好型解决方案）：

func textField(_ textField: UITextField,
               shouldChangeCharactersIn range: NSRange,
               replacementString string: String) -> Bool {
        guard let currentString = textField.text as NSString? else {
            return false
        }
        let newString = currentString.replacingCharacters(in: range, with: string)
        return Double(newString) != nil
}

Answer 29

Swift 3

    func textField(_ textField: UITextField, shouldChangeCharactersIn range: NSRange, replacementString string: String) -> Bool {
    if textField==yourTextFieldOutlet {
                if(CharacterSet.decimalDigits.isSuperset(of: CharacterSet(charactersIn: yourTextFieldOutlet.text!))){
//if numbers only, then your code here
                }
                else{
                showAlert(title: "Error",message: "Enter Number only",type: "failure")
                }
            }
    return true
    }

Answer 30

如果要允许小数分隔符和/或负数，可以使用此代码。但是这段代码允许例子：“34。” （更改文本时的结尾处的小数点分隔符）。所以你必须添加一些代码示例：textFieldShouldReturn或textFieldShouldEndEditing委托函数。

用Swift 4编写的代码，但我认为这与Swift 3兼容。

func textField(_ textField: UITextField, shouldChangeCharactersIn range: NSRange, replacementString string: String) -> Bool {
    guard let text = textField.text else {
        return true
    }

    let replaced = (text as NSString).replacingCharacters(in: range, with: string)
    let decimalSeparator = NSLocale.current.decimalSeparator ?? ""

    // When user wants to delete las character
    if replaced == "" || replaced == "-" || replaced == "-0" {
        textField.text = "0"
        return false
    }

    // When text contains 0 before replace except "0."
    if replaced != "0" + decimalSeparator && replaced.hasPrefix("0") && text.underestimatedCount == 1 {
        textField.text = replaced.substring(from: replaced.index(after: replaced.startIndex))
        return false
    }

    // When user wants to delete minus sign
    if text.hasPrefix("-") && text.substring(from: text.index(after: text.startIndex)) == replaced {
        return false
    }

    // When user wants to delete before decimal separator
    if replaced.hasPrefix(decimalSeparator) || replaced.hasPrefix("-" + decimalSeparator) {
        return false
    }

    // When user wants to add zero the beginning of number... but allowing "0." or "-0." numbers
    let testReplaced = replaced.hasPrefix("-") ? replaced.substring(from: replaced.index(after: replaced.startIndex)) : replaced
    if testReplaced.count >= 2 && testReplaced.hasPrefix("0") && !testReplaced.hasPrefix("0" + decimalSeparator) {
        return false
    }

    // Every other cases
    let allowDecimal = self.allowFloat ? (decimalSeparator == "." ? "\\.?" : decimalSeparator + "?") : ""
    let allowSign = self.allowSigned ? "-?" : ""
    let pattern = "\(allowSign)[0-9]+\(allowDecimal)([0-9]+)?"

    do {
        let regexRange = (replaced as NSString).range(of: replaced)
        let regex = try NSRegularExpression(pattern: pattern, options: [])
        let matches = regex.matches(in: replaced, options: [], range: regexRange)
        return matches.count == 1 && matches.first!.range == regexRange
    }
    catch {}

    return false
}

如果您不想允许小数或负数，则必须用下一行替换tow变量

let allowDecimal = ""
let allowSign = ""

Answer 31

您可以使用shouldChangeCharactersInRange和String扩展方法来检查输入字符串是否为数字。

extension String  {

    var isNumber : Bool {
        get{
            return !self.isEmpty && self.stringWithoutWhitespaces.rangeOfCharacter(from: CharacterSet.decimalDigits.inverted) == nil
        }
    }

    var stringWithoutWhitespaces: String {
        return self.replacingOccurrences(of: " ", with: "")
    }

}

//Mark: shouldChangeCharactersInRange
func textField(textField: UITextField, shouldChangeCharactersInRange range: NSRange, replacementString string: String) -> Bool {
    // return true if the string only contains numeric characters
    let isValid = string.stringWithoutWhitespaces.isNumber 
    return valid
}

Answer 32

Swift 2.0

func textField(textField: UITextField,
    shouldChangeCharactersInRange range: NSRange,
    replacementString string: String) -> Bool {

        let inverseSet = NSCharacterSet(charactersInString:"0123456789").invertedSet

        let components = string.componentsSeparatedByCharactersInSet(inverseSet)

        let filtered = components.joinWithSeparator("")

        return string == filtered

  }

Answer 33

func isValidNumber(str:String) -> Bool{
    if str.isEmpty {
        return false
    }
    let newChar = NSCharacterSet(charactersInString: str)
    let boolValid = NSCharacterSet.decimalDigitCharacterSet().isSupersetOfSet(newChar)
    if boolValid{
        return true
    }else{
        let lst = str.componentsSeparatedByString(".")
        let newStr = lst.joinWithSeparator("")
        let currentChar = NSCharacterSet(charactersInString: newStr)
        if lst.count == 2 && !lst.contains("") && NSCharacterSet.decimalDigitCharacterSet().isSupersetOfSet(currentChar){
            return true
        }
        return false
    }
}

如果有此功能，请将此功能放入“提交”或“保存”方法。

Answer 34

这是一个更易阅读的版本，可以做＆＃34; 0-9＆＃34;加上＃34;。＆＃34;：

func textField(textField: UITextField, shouldChangeCharactersInRange range: NSRange, replacementString string: String) -> Bool {

    let existingTextHasDecimal = textField.text?.rangeOfString(".")
    let replacementTextHasDecimal = string.rangeOfString(".")
    let replacementTextAllCharacters = NSCharacterSet(charactersInString: string)
    let replacementTextOnlyDigits = NSCharacterSet.decimalDigitCharacterSet().isSupersetOfSet(replacementTextAllCharacters)

    if replacementTextHasDecimal != nil && existingTextHasDecimal != nil {
        return false
    }else{
        if replacementTextOnlyDigits == true {
            return true
        }else if replacementTextHasDecimal != nil{
            return true
        }else{
            return false
        }
    }
}

Answer 35

首先添加delegate

的keyBoradType和textField

textField.delegate=self; textField.keyboardType = UIKeyboardTypeNumberPad;

比必须使用textField.delegate方法 -

- (BOOL) textField: (UITextField *)theTextField shouldChangeCharactersInRange:(NSRange)range replacementString: (NSString *)string 
{
  if (!string.length)
  {
       return YES;
  }

  if ([string intValue])
  {
        return YES;
  }

  return NO;
}

Answer 36

//只接受十进制数作为输入，[SWIFT 3.0]

func textField(_ shouldChangeCharactersIntextField: UITextField, shouldChangeCharactersIn range: NSRange, replacementString string: String) -> Bool
{
        let inverseSet = NSCharacterSet(charactersIn:"0123456789").inverted

        let components = string.components(separatedBy: inverseSet)

        let filtered = components.joined(separator: "")

        return string == filtered
}

Answer 37

更新了Cian对Swift 3的回应：

func textField(textField: UITextField,shouldChangeCharactersInRange range: NSRange,replacementString string: String) -> Bool { let newCharacters = NSCharacterSet(charactersIn: string) let boolIsNumber = NSCharacterSet.decimalDigits.isSuperset(of:newCharacters as CharacterSet) if boolIsNumber == true { return true } else { if string == "." { let countdots = textField.text!.components(separatedBy:".").count - 1 if countdots == 0 { return true } else { if countdots > 0 && string == "." { return false } else { return true } } } else { return false } } }

如何限制UITextField只接受Swift中的数字？

37 个答案: