如何在jquery中访问对象

Question

var v = [{"filename":"1.mp4","resname":"1280x720","videolength":"00:00:26.07"},{"filename":"2.mp4","resname":"854x480","videolength":"00:00:26.07"},{"filename":"3.mp4","resname":"640x360","videolength":"00:00:26.07"}];

我正在使用$.parseJSON(v);但是有错误，有任何建议可以获得resname的价值吗？

Answer 1

无需解析v您可以通过不同方式访问它

一个是迭代或forloop

v.forEach(function (item, i) {
    alert(item.resname)
});

您还可以使用

直接访问元素

 alert(v[0].filename);
alert(v[1].filename);

Answer 2

尝试：

var v = [{"filename":"1.mp4","resname":"1280x720","videolength":"00:00:26.07"},{"filename":"2.mp4","resname":"854x480","videolength":"00:00:26.07"},{"filename":"3.mp4","resname":"640x360","videolength":"00:00:26.07"}];

$.each(v,function (i, val) {
    console.log(val.resname)
});