My code is as follows:
//Node class (inner class)
private class Node
{
private String command;
private String fileName;
private int fileSize;
private Node next;
private Node prev;
//constructor of Node
private Node(String command, String fileName, int fileSize, Node prev, Node next)
{
this.command = command;
this.fileName = fileName;
this.fileSize = fileSize;
this.prev = prev;
this.next = next;
}
}
private Node head;
private Node tail;
int size;
//constructor of list
public ReadInput()
{
diskSize = 0;
head = null;
tail = null;
size = 0;
}
public void insert(String command, String fileName, int fileSize)
{
if (head == null)
{
head = tail = new Node(command, fileName, fileSize, null, null );
size ++;
}
else
{
for(Node temp = head; temp != null; temp = temp.next)
{
temp.next = new Node(command, fileName, fileSize, temp, temp.next.next);
temp.next.next.prev = temp.next;
size++;
if ( fileName == temp.fileName)
System.out.println("ID already exists!");
break;
}
}
}
我只是想插入我的双向链表。我有另一种方法,调用插入与适当的参数添加到我没有在这里发布的链表,因为它是不必要的。第一次插入头部很好但是在第二次插入时,在调试我的程序时,我发现我在行temp.next = new Node(command, fileName, fileSize, temp, temp.next.next);
上得到一个空指针异常
我无法看到我出错的地方有人可以帮忙吗?感谢
答案 0 :(得分:0)
对于您插入的第一个元素,以空列表开头,以便它通过if块
head = tail = new Node(command, fileName, fileSize, null, null );
所以head.next = null
当您插入第二个元素时,代码会跳转到else块
temp.next = new Node(command, fileName, fileSize, temp, temp.next.next);
如果是第二项,
temp = head
temp.next = null
temp.next.next =>空引用异常(传递给构造函数的最后一个参数)
另外,查看代码,似乎不是将temp.next.next传递给要传递temp.next的构造函数。将该陈述改为
temp.next = new Node(command, fileName, fileSize, temp, temp.next);