Question

如何使用此代码为上传的文件创建唯一ID。

代码上传图片，但是当您使用iPhone上传图片时，所有图片都会显示为image.jpg。所以我需要一个函数来重命名现有文件，或者只为每个文件创建唯一的id。

<form enctype="multipart/form-data" action="" method="POST"> Please choose a file: <input name="uploaded" type="file" /><br /> <input type="submit" value="Upload" /> </form>
<?php 
function findexts ($filename)  {  $filename = strtolower($filename) ;  $exts = split("[/\\.]", $filename) ;  $n = count($exts)-1;  $exts = $exts[$n];  return $exts;  }   

$ext = findexts ($_FILES['uploaded']['name']) ; 


$ran = rand () ; 
$ran2 = $ran.".";  
$target = "uploads/";

if(file_exists("uploads/$filename")) unlink("uploads/$filename");move_uploaded_file($target, "uploads/$filename");

if(move_uploaded_file($_FILES['uploaded']['tmp_name'], $target))  { echo "The file has been uploaded as ".$ran2.$ext; }  else { echo "Sorry, there was a problem uploading your file."; } 
$target = $target . $ran2.$ext;

Answer 1

您可以将uniqid()功能用于唯一的图像名称。它有两个参数。第一：前缀，第二：更多熵。

请在此处查看详细信息：http://php.net/manual/en/function.uniqid.php

 <form enctype="multipart/form-data" action="" method="POST"> Please choose a file: <input name="uploaded" type="file" /><br /> <input type="submit" value="Upload" /> </form>
    <?php 
    function findexts ($filename)  {  
       $filename = strtolower($filename) ;  
       $exts = split("[/\\.]", $filename) ;  
       $n = count($exts)-1;  
       $exts = $exts[$n];  return $exts;  
    }   

    $ext = findexts ($_FILES['uploaded']['name']) ; 

    //unique image
    $new_image_name = uniqid("IMG_",false);
    $final_name = $new_image_name.".".$ext;

    //Target directory
    $target = "uploads/";

    if(file_exists("uploads/$final_name")) unlink("uploads/$final_name");move_uploaded_file($target,"uploads/$final_name");

    if(move_uploaded_file($_FILES['uploaded']['tmp_name'], $target))  { echo "The file has been uploaded as ".$final_name; }  else { echo "Sorry, there was a problem uploading your file."; } 
    $target = $target . $final_name;

为上传的图片创建唯一ID

1 个答案: