我试图回应整个HTML代码。我正在使用基础5,如果我尝试在php代码块中创建一个表单变量,则会出现一个错误,指出基础5中使用的类不可用。正如您所看到的,这不是一个完成的代码,所以我现在只是在寻找答案。
这是我的代码:
<?php
session_start();
?>
<!doctype html>
<html class="no-js" lang="en">
<head>
<meta charset="utf-8" />
<meta name="viewport" content="width=device-width, initial-scale=1.0" />
<title>AskmanProducts</title>
<link rel="stylesheet" href="css/foundation.css" />
<script src="js/vendor/modernizr.js"></script>
<script src="js/signinvaldator.js"></script>
</head>
<body>
<div class="row" style="margin-top:10%">
<div align="center"><h2>Log In To Access This Website</h2></div>
<br />
<div class="medium-6 medium-centered large-centered large-6 columns">
<form data-abide>
<div class="name-field">
<label for="username">Username</label>
<input id="username" type="text" required="" name="user"></input>
<small class="error" data-error-message="">A username is required.</small>
</div>
<label for="password">Password</label>
<input id="password" type="password" required="" name="password"></input>
<small class="error">A Password is required.</small>
<br />
<br />
<button type="submit" name="loginbtn">Log In</button>
<a href="signup.php" class="button">Sign Up</a>
<a href="forgotpass.php" class="button">Forgot Password?</a>
<br />
</form>
</div>
</div>
<?php
if ($_POST['loginbtn']) {
$user = $_POST['user'];
$password = $_POST['password'];
}
else
echo
?>
<script src="js/vendor/jquery.js"></script>
<script src="js/foundation.min.js"></script>
<script>
$(document).foundation();
</script>
</body>
</html>
答案 0 :(得分:0)
将您的html文件重命名为php。示例:index.html - &gt;的index.php