Question

我是spring的新手。虽然我的Tomcat日志显示我的URL已映射，但我的映射无法正常工作。

INFO: Mapped URL path [/movie/{name}] onto handler 'movieController'
Jun 21, 2015 9:03:24 PM org.springframework.web.servlet.handler.AbstractUrlHandlerMapping registerHandler
INFO: Mapped URL path [/movie/{name}.*] onto handler 'movieController'
Jun 21, 2015 9:03:24 PM org.springframework.web.servlet.handler.AbstractUrlHandlerMapping registerHandler
INFO: Mapped URL path [/movie/{name}/] onto handler 'movieController'
Jun 21, 2015 9:03:24 PM org.springframework.web.servlet.handler.AbstractUrlHandlerMapping registerHandler
INFO: Mapped URL path [/movies] onto handler 'movieController'
Jun 21, 2015 9:03:24 PM org.springframework.web.servlet.handler.AbstractUrlHandlerMapping registerHandler
INFO: Mapped URL path [/movies.*] onto handler 'movieController'
Jun 21, 2015 9:03:24 PM org.springframework.web.servlet.handler.AbstractUrlHandlerMapping registerHandler
INFO: Mapped URL path [/movies/] onto handler 'movieController'
Jun 21, 2015 9:03:24 PM **org.springframework.web.servlet.handler.AbstractUrlHandlerMapping registerHandler
INFO: Mapped URL path [/employeelist] onto handler 'userList'
Jun 21, 2015 9:03:24 PM org.springframework.web.servlet.handler.AbstractUrlHandlerMapping registerHandler
INFO: Mapped URL path [/employeelist.*] onto handler 'userList'
Jun 21, 2015 9:03:24 PM org.springframework.web.servlet.handler.AbstractUrlHandlerMapping registerHandler
INFO: Mapped URL path [/employeelist/] onto handler 'userList'

我在web.xml中定义了两个控制器。

<web-app id="WebApp_ID" version="2.4"
    xmlns="http://java.sun.com/xml/ns/j2ee"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee 
    http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd">

    <display-name>Spring Web MVC Application</display-name>


    <servlet>       <servlet-name>mvc-dispatcher</servlet-name>
        <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
        <load-on-startup>1</load-on-startup>    </servlet>

    <!-- for ListDispatcher -->

    <servlet>       <servlet-name>list-dispatcher</servlet-name>
        <servlet-class>org.apache.cxf.transport.servlet.CXFServlet</servlet-class>
        <load-on-startup>1</load-on-startup>    </servlet>


    <servlet-mapping>       <servlet-name>mvc-dispatcher</servlet-name>
        <url-pattern>/test/*</url-pattern>  </servlet-mapping>


    <servlet-mapping>       <servlet-name>list-dispatcher</servlet-name>
        <url-pattern>/list/*</url-pattern>  </servlet-mapping>


<context-param>   <param-name>contextConfigLocation</param-name>  
<param-value>
    /WEB-INF/list-dispatcher-servlet.xml
    /WEB-INF/mvc-dispatcher-servlet.xml   </param-value> </context-param>

    <!-- <listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
        </listener> --> 
</web-app>

我正在获取MovieController中定义的输出。 http://localhost:8080/SpringMVC/test/movies

但是当我提供URL来获取employeeelist（另一个控制器）时。不工作.Below是控制器类。： -

@Controller

public class UserList {


    public ModelAndView getdata() {
        System.out.println("Data");

        ArrayList<Employee> list = getEmpList();

        //return back to index.jsp
        ModelAndView model = new ModelAndView("index");
        model.addObject("lists", list);

        return model;

    }

    @RequestMapping(value="/employeelist", method = RequestMethod.GET) 
    public @ResponseBody  ArrayList<Employee> getEmpList(){
        System.out.println("inside The ArrayList");
        ArrayList<Employee> emp=new ArrayList<Employee>();
        emp.add(new Employee("sougata",25));
        emp.add(new Employee("sahil",30));
        return emp;

    }
}

有人请求帮助我从第二个控制器获得响应。我使用的网址是： - http://localhost:8080/SpringMVC/list/employeelist

Answer 1

更改应用程序中的片段代码。

在您的情况下，您已将两个控制器分开以进行多项操作。因此，根据您的案例场景，在web.xml中替换此代码段，如此

<servlet-mapping>
     <servlet-name>mvc-dispatcher</servlet-name>
     <url-pattern>/</url-pattern>
</servlet-mapping>

并更改控制器类中的控制器请求映射，对于电影控制器添加像这样，

@Controller
@RequestMapping("/movieController")
public class MovieController {

用于userList控制器添加如下，

@Controller
@RequestMapping("/userListController")
public class UserList {

检查dispatcher-servlet.xml中正确提到的基于组件的包属性。

Answer 2

尝试将produce =“application / json”添加到您的@RequestMapping中，如下所示。

@RequestMapping（value =“/ employeelist”，method = RequestMethod.GET，produce =“application / json”）

Answer 3

您是否尝试集成spring MVC和CXF服务？ list-dispatcher的servlet类是web.xml中的CXFServlet。 org.apache.cxf.transport.servlet.CXFServlet 如果不是 - 您实际上不需要两个不同的servlet配置。只需要下面的

<web-app xmlns="http://java.sun.com/xml/ns/j2ee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd"
    version="2.4">
    <servlet><servlet-name>mvc-dispatcher</servlet-name>
        <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
        <load-on-startup>1</load-on-startup>
    </servlet>
    <servlet-mapping>
        <servlet-name>mvc-dispatcher</servlet-name>
        <url-pattern>/*</url-pattern>
    </servlet-mapping>
</web-app>

映射多个控制器的问题

3 个答案: