Question

这里新（和Java！）。我在网站上搜索了我的问题的答案，但没有结果。该程序最多执行scan.nextDouble语句。

如果我输入薪水值，例如“8”，我会得到：

/////OUTPUT/////  
Enter the performance rating (Excellent, Good, or Poor):  
Current Salary:       $8.00  
Amount of your raise: $0.00  
Your new salary:      $8.00  
/////END OF OUTPUT/////

很明显，我的以下scan.nextLine和所有if-else语句都被绕过了。我错过了什么？

    import java.util.Scanner;
    import java.text.NumberFormat;

public class Salary 
{

    public static void main(String[] args) 
    {
        double currentSalary;  // employee's current  salary
        double raise = 0;          // amount of the raise
        double newSalary = 0;      // new salary for the employee
        String rating;         // performance rating
        String rating1 = new String("Excellent");
        String rating2 = new String("Good");
        String rating3 = new String("Poor");

        Scanner scan = new Scanner(System.in);

        System.out.print ("Enter the current salary: ");
        currentSalary = scan.nextDouble();
        System.out.print ("Enter the performance rating (Excellent, Good, or Poor): ");
        rating = scan.nextLine();

        // Compute the raise using if ...
        if (rating.equals(rating1))

            raise = .06;

        else

        if (rating.equals(rating2))

            raise = .04;

        else

        if (rating.equals(rating3))

            raise = .015;

        else

            newSalary = currentSalary + currentSalary * raise;

         // Print the results
        {
        NumberFormat money = NumberFormat.getCurrencyInstance();
        System.out.println();
        System.out.println("Current Salary:       " + money.format(currentSalary));
        System.out.println("Amount of your raise: " + money.format(raise));
        System.out.println("Your new salary:      " + money.format(newSalary));
        System.out.println();
        }
    }
}

Answer 1

Scanner.nextDouble（）只读取下一个可用的double值，而不是指向下一行。

在实际的之前使用虚拟scanner .nextLine（）。使光标指向scan.nextline（）从中获取输入的下一行。

-cheers：）

Answer 2

当你使用scanner.nextDouble（）扫描输入时，它只接受浮点值并在缓冲区中留下新行字符，所以当你执行scanner.nextLine（（）它接受新行字符并返回空字符串。在扫描下一行之前输入另一个scanner .nextLine（）以占用新行字符

currentSalary = scan.nextDouble();
    System.out.print ("Enter the performance rating (Excellent, Good, or Poor): ");
    scan.nextLine(); 
    rating = scan.nextLine();

跳过系统，扫描nextLine和if循环

2 个答案: